C语言 即使在出现错误后，程序仍保持运行

Question

我有一个程序可以将文件中的一些数字检索到数组中。我遇到的最后一个问题是我的程序即使无法打开文件，也会继续运行，而不是结束它。即使它说程序结束，main的菜单也会再次出现，但不显示任何数据

int main (void)
{ 
int choice, max, min;
float avg;
int test[MAX_NUMBER_OF_STUDENTS];
int file_opened;
int number_of_students;
file_opened = get_test_scores(test, &number_of_students);
if (file_opened == 0)
{
  do
  {
    choice = menu();
    switch (choice)
    {
    case 0: printf("nProgram is over.n");
              break;
    case 1: test_avg(&avg, test, number_of_students);
            printf("nAverage score on test = %5.2fn", avg);
            break;
    case 2: test_max_min(number_of_students, &max, &min, test);
            printf("nMaximum score = %3dn"
                      "Minimum score = %3dn", max, min);
            break;
    case 3: print_test(test,number_of_students);
            break;
    default:
            printf("This should never happen!");
  }
  } while (choice != 0);
}
return 0;
 }
int get_test_scores(int test[], int* size)
{
FILE* sp_input;    // Pointer to the input stream (from a file)
  int i;
 sp_input = fopen("a20.dat", "r");                                               
  if (sp_input == NULL)
     printf("nUnable to open the file a20.datn");
  else
  {
    while( fscanf(sp_input, "%d", &test[i])!=EOF)
    {
    i=i+1;
    ++*size;
    }
    fclose(sp_input);    // Close the stream
  }
  return 1;
}

Answer 1

是的，它一直在运行...

if (file_opened == 0)
{
  do
  {

表示如果文件尚未打开，则执行循环。你想要：

if (file_opened != 0)

另请参阅有关其他错误的评论。