如何改进在 >= ES6 中返回创建的时间差异(30 秒、5 分钟、3 小时、1 年前)的方法

Question

这是我的代码

我试图实现的是类似于youtube/FB/Instagram的时间，显示发布时间差异

喜欢： 30多年前 5m前 15小时前 6天前 1w前 5年前

代码工作正常，但很冗长，我想知道一些 js "guru"是否可以使用 ECMASCRIPT 的最新功能来改进它

const timeAgo = () => {
const date1 = dayjs(Date.now())
const now = base.createdOn
const diffInSeconds = date1.diff(now, 'second', false)
let diff = date1.diff(now, 'second', false) + 's'
if (diffInSeconds > 60 * 60 * 24 * 7 * 30 * 12) {
return date1.diff(now, 'year', false) + 'y'
}
if (diffInSeconds > 60 * 60 * 24 * 7 * 30) {
return date1.diff(now, 'month', false) + 'm'
}
if (diffInSeconds > 60 * 60 * 24 * 7) {
return date1.diff(now, 'week', false) + 'w'
}
if (diffInSeconds > 60 * 60 * 24) {
return date1.diff(now, 'day', false) + 'd'
}
if (diffInSeconds > 60 * 60) {
return date1.diff(now, 'hour', false) + 'h'
}
if (diffInSeconds > 60) {
return date1.diff(now, 'minute', false) + 'm'
}
return diff
}

Answer 1

for of应该这样做，如果你让day.js比较，你就不会有逻辑错误：

const timeSince = (from, to = Date.now()) => {
to = dayjs(to);
const units = ['year', 'month', 'week', 'day', 'hour', 'minute'];
for (let unit of units){
const diff = to.diff(from, unit, false);
if(diff) {
return diff + unit.charaAt(0); // you are using m for month and minute...
}
}
// base case if there are no seconds difference
return to.diff(now, 'second', false) + 's';
}
// timeSince(base.createdOn)