如何检查两个数组是否有相同的元素，而不管它们的索引位置

Question

你能让我知道我如何检查两个数组是否具有相同的元素，并返回true或false，无论它们的元素索引位置如何?你可以看到$a==$b没有这样做

$a = array("apple","banana", "strawberry");
$b = array("strawberry", "apple","banana");
if($a==$b){
   echo "yes";
}else{
 echo "no";
}

Answer 1

Use Array Diff:

$a = array("apple","banana", "strawberry");
$b = array("strawberry", "apple","banana");

$result = array_diff($a, $b);
if(count($result) > 0){
   echo "yes";
}else{
   echo "no";
}

Answer 2

只需将您的数组对象包含在sort()函数中，同时比较它们

$a = array("apple","banana", "strawberry");
$b = array("strawberry", "apple","banana");
if(sort($a) == sort($b)){
    echo "yes";
}else{
    echo "no";
}

Answer 3

您可以sort()两个数组，然后检查是否相等。这样的:

<?php
$a=array("apple","banana", "strawberry");
$b=array("strawberry", "apple","banana");
$a = sort($a);
$b = sort($b);
if($a==$b){
   echo "yes";
}else{
 echo "no";
}
?>

Answer 4

可以使用array_diff()函数

$a = array("apple","banana", "strawberry");
$b = array("strawberry", "apple","banana");
$diff = array_diff($a, $b);
if(count($diff) > 0){
   echo "yes";
}
else{
   echo "no";
}
print_r($diff);

如果$diff返回一个空数组，则表示$a与$b之间没有区别。

否则，$diff返回不同的元素。

查看手册，array_diff