>我有两个具有以下结构的对象,并尝试将它们合并在一起。
我尝试了 $.merge,但这不是预期的结果。
对象 1 - 没有所有属性
{
"id": 23,
"name": "Article",
"related": 15 "items": [{
"name": "Test1",
"items": [{
"name": "Test2",
"items": [{
"name": "Test3",
"items": [{
"name": "Test4",
"items": [{
"name": "Test5",
"items": [{
"name": "Test6",
}]
}]
}]
}]
}]
}]
}, {
"id": 24…
}
对象 2 - 具有其他属性
{
"id": 23,
"name": "Article",
"related": 15 "items": [{
"name": "Test1",
"id": 34 "items": [{
"name": "Test2",
"id": 57 "items": [{
"name": "Test3",
"id": 92 "items": [{
"name": "THIS ONE IS NOT EXISTING IN OBJECT 1 AND SHOULD NOT GET MERGED",
"id": 789
}, {
"name": "Test4",
"id": 12 "items": [{
"name": "Test5",
"id": 321 "items": [{
"name": "Test6",
"id": 285
}]
}]
}]
}]
}]
}]
}, {
"id": 24…
}
有谁知道一些聪明的把戏?jQuery甚至有必要吗?
jQuery的$.extend 将做你想做的事。
//merging two objects into new object
var new_object = $.extend(true, {}, object1, object2);
//merge object2 into object1
$.extend(true, object1, object2);
第一个参数:deep:true,参见:https://api.jquery.com/jquery.extend/
Without jquery: https://jsfiddle.net/sLhcbewh/
function mymerge_sub(object1, object2)
{
for(var i in object2) {
if(i == 'items')
continue;
console.log(i);
if(object1[i] === undefined) {
console.log(i + ' not found');
object1[i] = object2[i];
}
}
if(object1.items !== undefined) {
mymerge_sub(object1.items[0], object2.items[0])
}
}
function mymerge(object1, object2) {
var ret = JSON.parse(JSON.stringify(object1));
mymerge_sub(ret, object2); // save obj 1
return ret;
}
var obj3 = mymerge(obj1, obj2);
如果你想要多个项目,你必须循环mymerge_sub(object1.items[j]...)。