我正在制作一个程序将数组列表发布到服务器,然后解析数组列表并将其存储在数据库中,但我无法读取响应有人可以帮助我,因为我无法鳞翅目
这是安卓java代码:-
public void confirmOrder(final String name, final String price, final String quantity, final String cost, final String sellerid)
{
AsyncHttpClient httpClient = new AsyncHttpClient();
RequestParams params = new RequestParams();
ArrayList<HashMap<String,String>> productList= dbHelper.getAllProducts();
if(productList.size()!=0)
{
pDialog.show();
params.put("OrderSummary",dbHelper.getAllproducts());
httpClient.post(APIURL.API_URL, params, new AsyncHttpResponseHandler() {
@Override
public void onSuccess(int statusCode, Header[] headers, byte[] responseBody) {
}
@Override
public void onFailure(int statusCode, Header[] headers, byte[] responseBody, Throwable error) {
}
});
}
else
{
Toast.makeText(getApplicationContext(),"List Empty",Toast.LENGTH_LONG).show();
}
}
这是PHP代码:-
$json = $_POST["usersJSON"];
//Remove Slashes
if (get_magic_quotes_gpc()){
$json = stripslashes($json);
}
//Decode JSON into an Array
12
$data = json_decode($json);
//Util arrays to create response JSON
$a=array();
$b=array();
//Loop through an Array and insert data read from JSON into MySQL DB
for($i=0; $i<count($data) ; $i++)
{
//inserting data in to the database
i++;
}
if(i<0)
{
$response['error']=true;
$response['message']="data inserted";
}
else
{
$response['error']=false;
$response['message']="error occured";
}
echo json_encode ($response)
如何在我的 Java 程序中读取此响应?
> 在 onSuccess 中检查 http 状态代码 200,然后像这样解析响应字节数组
String str = IOUtils.toString(responseBody, "UTF-8");
之后使用 Gson 将 json Sting 解析到任何 POJO。对成功和失败都做同样的事情。