温莎城堡注册开放式通用Ilogger

Question

我有简单的喷油器注册：

container.RegisterConditional(typeof(ILogManager),
c => typeof(LogManager<>).MakeGenericType(c.Consumer.ImplementationType),
Lifestyle.Singleton,
c => true);

我需要使用温莎城堡在不同的项目中注册同一logmanager。

我尝试了

container.Register(Component.For(typeof(ILogger))
            .ImplementedBy(typeof(Log4NetLogger<>).MakeGenericType())
            .LifeStyle.Singleton.Start());

无法使其工作。

Answer 1

不幸的是，这对城堡更为复杂。但是，您可以使用亚依赖性质量验证者获得相同的结果：

public class LoggerResolver : ISubDependencyResolver
{
    public bool CanResolve(CreationContext context, ISubDependencyResolver contextHandlerResolver, ComponentModel model, DependencyModel dependency)
    {
        return dependency.TargetType == typeof(ILogger);
    }
    public object Resolve(CreationContext context, ISubDependencyResolver contextHandlerResolver, ComponentModel model, DependencyModel dependency)
    {
        var logger = typeof(LogManager<>).MakeGenericType(model.Implementation);
        return Activator.CreateInstance(logger);
    }
}

将其添加到内核中：

Kernel.Resolver.AddSubResolver(new LoggerResolver())

另一种方法是使用GeneriCimplementationMatchingStrategy。如果LogManager具有一些依赖性，则此情况也将在情况下工作：

public class OpenGenericAncestorMatchingStrategy : IGenericImplementationMatchingStrategy
{
    public Type[] GetGenericArguments(ComponentModel model, CreationContext context)
    {
        return new[] { context.Handler.ComponentModel.Implementation };
    }
}

和注册：

container.Register(Component.For<ILogger>().ImplementedBy(typeof(LogManager<>), new OpenGenericAncestorMatchingStrategy()));