弹性搜索使用 javascript 将 json 对象的数组平展为单级

Question

>我面临着将弹性查询响应(仅我想要_source详细信息(扁平化为单级数组的问题。

请在下面找到弹性响应：

使用(response.hits.hits(我能够访问数据数组，但无法将对象数组扁平化为单级

当前阵列 ：

var current_array = [
{
"_id": "gSdhs8aPjcUjiIs6ey85",
"_score": 1,
"_source": {
"business_type": "Primary Only",
"ceo_name": "Tim Cook",
"city": "San Ramon",
"company_id": "gSdhs8aPjcUjiIs6ey85",
"company_name": "Apple Inc."
}
},
{
"_id": "v2bdB5F3PbLzziayKikS",
"_score": 1,
"_source": {
"bankruptcy_activity": "No",
"business_type": "Primary Only",
"ceo_name": "Andrew N. Liveris",
"city": "New York",
"company_id": "v2bdB5F3PbLzziayKikS",
"company_name": "General Electric",
"country": "United States"
}
}
];

期望的结果：

var desired_array = [{
"_id": "gSdhs8aPjcUjiIs6ey85",
"_score": 1,
"_source_business_type": "Primary Only",
"_source_ceo_name": "Tim Cook",
"_source_city": "San Ramon",
"_source_company_id": "gSdhs8aPjcUjiIs6ey85",
"_source_company_name": "Apple Inc."
},
{
"_id": "v2bdB5F3PbLzziayKikS",
"_score": 1,
"_source_business_type": "Primary Only",
"_source_ceo_name": "Andrew N. Liveris",
"_source_city": "New York",
"_source_company_id": "v2bdB5F3PbLzziayKikS",
"_source_company_name": "General Electric",
"_source_country": "United States"
}
];

我尝试了下面的代码，但它正在转换为我不想要的单个数组：

var flattenObject = function (ob) {
var toReturn = [];
var flatObject;
for (var i in ob) {
if (!ob.hasOwnProperty(i)) {
continue;
}
if ((typeof ob[i]) === 'object') {
flatObject = flattenObject(ob[i]);
for (var x in flatObject) {
if (!flatObject.hasOwnProperty(x)) {
continue;
}
toReturn[i + (!!isNaN(x) ? '.' + x : '')] = flatObject[x];
}
} else {
toReturn[i] = ob[i];
}
}
return toReturn;
};

它给出的输出如下：

var undesired_array = [
0. _index: "company",
0. _score: 1,
0. _source.ceo_name: "Tim Cook",
0. _source.city: "San Ramon",
0. _source.company_name: "Apple Inc.",
1. _id: "v2bdB5F3PbLzziayKikS",
1. _index: "company",
1. _score: 1,
1. _source.ceo_name: "Andrew N. Liveris",
1. _source.city: "New York",
1. _source.company_id: "v2bdB5F3PbLzziayKikS",
1. _source.company_name: "General Electric"
];

Answer 1

考虑到每个对象中只有一个级别的嵌套，这段代码应该可以工作。

function flattenObject(input) {
return input.map(function (doc) {
let flatDoc = {};
Object.keys(doc).forEach(function (key) {
if (doc[key]instanceof Object) {
Object.keys(doc[key]).forEach(function (innerkey) {
flatDoc[key + "_" + innerkey] = doc[key][innerkey];
});
} else {
flatDoc[key] = doc[key];
}
});
return flatDoc;
});
}