我有一系列这样的坐标:
array = [[1,6],[2,6],[3,8],[4,10],[5,6],[5,7],[18,6],[19,5],[17,9],[10,5]]
我想在6
之间将数组分开。和7
。协调([5,7],[18,6])
,因为那里的X
值有差距。我想获得两个单独的数组arr1
和arr2
,其中arr1
是拆分之前的值,而arr2
是之后的值。
我想说的是,如果下一个X
值大于10
的差异,它将附加到arr2
,否则arr1
,类似的内容:
arr1 = []
arr2 = []
for [x,y] in array:
if next(x) > 10:
arr2.append(x,y)
else:
arr1.append(x,y)
有人可以帮助我解决这个问题吗?
如果我正确地得到了您的问题,您正在尝试在第一个点分开数组,其中两个随后的X值之间的差异大于10。您可以使用numpy做到这一点:
import numpy as np
THRESH = 10
array = [[1,6],[2,6],[3,8],[4,10],[5,6],[5,7],[18,6],[19,5],[17,9],[10,5]]
array = np.asarray(array)
deltas_x = np.abs(array[1:,0] - array[:-1,0])
split_idx = np.where(deltas_x > THRESH)[0][0] + 1
arr1 = array[:split_idx,:]
arr2 = array[split_idx:,:]
请注意,我们需要在NP的结果中添加1个,以说明deltas_x
数组比array
这可能是您正在寻找的
array = [[1,6],[2,6],[3,8],[4,10],[5,6],[5,7],[18,6],[19,5],[17,9],[10,5]]
# Declare two array variables
arr1 = None
arr2 = None
n = len(array)
for i in range(n-1):
if abs(array[i][0] - array[i+1][0]) >= 10:
arr1 = array[:i+1]
arr2 = array[i+1:]
break
print arr1
print arr2
您可以执行以下操作:
ar = np.array([[1,6],[2,6],[3,8],[4,10],[5,6],[5,7],[18,6],[19,5],[17,9],[10,5]])
# get differences of x values
dif = ar[1:, 0] - ar[:-1, 0]
# get the index where you first observe a jump
fi = np.where(abs(dif) > 10)[0][0]
ar1 = ar[:fi+1]
ar2 = ar[fi+1:]
然后dif
是:
array([ 1, 1, 1, 1, 0, 13, 1, -2, -7])
fi
为5,ar1
和ar2
为:
array([[ 1, 6],
[ 2, 6],
[ 3, 8],
[ 4, 10],
[ 5, 6],
[ 5, 7]])
和
array([[18, 6],
[19, 5],
[17, 9],
[10, 5]]),
分别。
这也允许您获得数据中的所有跳跃(您只需要将fi = np.where(abs(dif) > 10)[0][0]
更改为fi = np.where(abs(dif) > 10)[0]
)
可能最容易在连续的对上迭代并在发现差距后立即拆分:
array = [[1,6],[2,6],[3,8],[4,10],[5,6],[5,7],[18,6],[19,5],[17,9],[10,5]]
for idx, (cur, nxt) in enumerate(zip(array, array[1:])): # successive pairs and index
if abs(cur[0] - nxt[0]) > 10: # compare difference of first items
arr1, arr2 = array[:idx+1], array[idx+1:] # split
break # no further splits, end the loop now
else: # no break, keep the original array
arr1, arr2 = array, []
给出:
>>> arr1
[[1, 6], [2, 6], [3, 8], [4, 10], [5, 6], [5, 7]]
>>> arr2
[[18, 6], [19, 5], [17, 9], [10, 5]]
如果您想分裂几次会更加困难,但这应该很好。
在比较连续元素时,我通常会枚举:
array = [[1,6],[2,6],[3,8],[4,10],[5,6],[5,7],[18,6],[19,5],[17,9],[10,5]]
arr1 = list()
arr2 = list()
gap = 10
for index, value in enumerate(array[:-1]): # [:-1] prevents out of range
if abs(value[0]-array[index+1][0]) >= gap:
arr1.append(value)
else:
arr2.append(value)
arr2.append(array[-1]) # Take into account that the last element needs to be added to one of the arrays.
arry1 = []
arry2 = []
for i in arry:
if (i[0] - i[1]) > 10:
arry1.append(i)
else:
arry2.append(i)
尝试以下:
prev = array[0][0]
pos = -1
for i in range (1, len(array)):
if array[i][0] - prev >1:
break
else:
prev = array[i][0]
if pos != -1:
arr1 = array[:pos]
arr2 = array[pos:]
这应该按照您想要的方式拆分array
。请注意,列表是从0。