从日期开始提取日期和月份时，我该如何保持零

Question

我的日期看起来

2017-02-22
2017-02-23
2017-02-05

我需要以这种格式dd.mm提取日期，所以它看起来

23.02
22.02
05.02

但是这个

concat(day(PLAN_REPAYMENT_DATE_KEY), '.', month(PLAN_REPAYMENT_DATE_KEY))

返回

23.2
22.2
5.2

如何保持领先的零？

Answer 1

1. date_format(PLAN_REPAYMENT_DATE_KEY,'dd.MM') 
2. from_unixtime(unix_timestamp(PLAN_REPAYMENT_DATE_KEY),'dd.MM')
3. printf('%02d.%02d',day(PLAN_REPAYMENT_DATE_KEY),month(PLAN_REPAYMENT_DATE_KEY))

---

hive> with t as (select date '2017-02-05' as PLAN_REPAYMENT_DATE_KEY)
    > select date_format(PLAN_REPAYMENT_DATE_KEY,'dd.MM') from t;
OK
05.02

---

hive> with t as (select date '2017-02-05' as PLAN_REPAYMENT_DATE_KEY) 
    > select from_unixtime(unix_timestamp(PLAN_REPAYMENT_DATE_KEY),'dd.MM') from t;
OK
05.02

---

hive> with t as (select date '2017-02-05' as PLAN_REPAYMENT_DATE_KEY)
    > select printf('%02d.%02d',day(PLAN_REPAYMENT_DATE_KEY),month(PLAN_REPAYMENT_DATE_KEY)) from t;
OK
05.02

Answer 2

concat(LPAD(day(PLAN_REPAYMENT_DATE_KEY), 2, '0'), '.', LPAD(MONTH(PLAN_REPAYMENT_DATE_KEY), 2, '0'))

编辑：也添加了LPAD。