2错误:表达非法开始[Java]

Question

我尚未完成此操作，但是如果我已经有错误，则没有任何进展。这是我的代码..

public static void main(String[] args)
{
    Scanner inputDevice = new Scanner(System.in);
    System.out.print("Please enter the name of student ==> ");
    studentName = inputDevice.nextInt();
    inputDevice.nextLine();
    System.out.printIn("Enter the mark for student "+ studentName " out of 65 ==> ");
    studentMark = inputDevice.nextInt();
    inputDevice.nextLine();
}

第一个错误：'('预期

System.out.printIn("Enter the mark for student "+ studentName " out of 65 ==> ");

第二错误：表达式

非法开始

System.out.printIn("Enter the mark for student "+ studentName " out of 65 ==> ");

我很新。我不明白为什么我的第二张打印给我错误

Answer 1

基本上，几乎所有内容在这里是错误的。

问题＃1-行3

studentName = inputDevice.nextInt();

您没有正确声明studentName。当您想要一个名称(String(时，您还试图获得int。相反，该行应该读：

String studentName = inputDevice.nextLine();

问题＃2-行4

inputDevice.nextLine();

这条线在这里做什么？您没有将输入分配给任何内容。只需完全删除这条线即可。

问题＃3-行5

System.out.printIn("Enter the mark for student "+ studentName " out of 65 ==> ");

您缺少+。这条线应读：

System.out.printIn("Enter the mark for student "+ studentName +" out of 65 ==> ");

问题＃4-行6

studentMark = inputDevice.nextInt();

再次，您没有正确声明该变量。应该是：

int studentMark = inputDevice.nextInt();

问题＃5-行7

inputDevice.nextLine();

就像第2期一样，这条线一无所获。删除它。

摘要

您的代码应该(可能(这样读取：

    Scanner inputDevice = new Scanner(System.in);
    System.out.print("Please enter the name of student ==> ");
    String studentName = inputDevice.nextLine();
    System.out.println("Enter the mark for student "+ studentName + " out of 65 ==> ");
    int studentMark = inputDevice.nextInt();

Answer 2

替换此

System.out.printIn("Enter the mark for student "+ studentName " out of 65 ==> ");

System.out.printIn("Enter the mark for student "+ studentName +" out of 65 ==> ");

Answer 3

我认为您没有按照应有的声明变量。扫描仪输入= new Scanner(System.in(;

String studentName = inputDevice.nextLine(); int studentMark = inputDevice.nextInt();