如何做多维数组交叉使用lodash

Question

我正在使用lodash在javascript中做一个数组交集，下面是我正在尝试的代码，我得到的是

["universal", "ola", "uber", "bangalore"], 

但是，我期待的是["普遍"]

这里，orgArr具有n个项目的多维数组，我的意思是，orgArr可以有5个或6个或10个项目…示例

[["garden","canons","philips","universal"],["universal","ola","uber","bangalore"], ["ola","uber","bangalore"]];

不只是两个项目请注意

var orgArr = [["garden","canons","philips","universal"],["universal","ola","uber","bangalore"]];
    var resfinaArray = [];

    for (var i = 0; i < orgArr.length; i++){
         var currItem = orgArr[i];
         for (var j = 0; j< orgArr.length; j++){
         resfinaArray.push(_.intersection(currItem, orgArr[j]));
         }
    }
    console.log(resfinaArray, 'resfinaArray');

请帮忙好吗?

Answer 1

您可以使用forEach()循环和可选的thisArg参数。

var orgArr = [["garden","canons","philips","universal"],["universal","ola","uber","bangalore"]];
var resfinaArray = [];
orgArr.forEach(function(a) {
  var that = this;
  a.forEach(function(e) {
    (!that[e]) ? that[e] = true : resfinaArray.push(e);
  })
}, {});
console.log(resfinaArray);

Answer 2

我将按以下方法做这项工作;

var intersectArrays = a => a.reduce((p,c) => p.filter(e => c.includes(e))),
                arr = [["garden","canons","philips","universal"],["universal","ola","uber","bangalore"], ["ola","uber","bangalore", "universal"]],
                brr = intersectArrays(arr);
console.log(brr);

Answer 3

对于ES6，您可以使用Set和Array#reduce。

var array = [["garden", "canons", "philips", "universal"], ["universal", "ola", "uber", "bangalore"], ["abc", "def", "universal"]],
    result = [...array.reduce((r, a, i) => 
        a.reduce((s, b) =>
            (!i || r.has(b)) && s.add(b) || s, new Set), new Set)];
   
console.log(result);

Answer 4

你不需要循环:

var intersection = _.intersection(["garden","canons","philips","universal"],["universal","ola","uber","bangalore"]);

如果你有你的数据在数组中，你可以使用apply:

var intersection = _.intersection.apply(null, [["garden","canons","philips","universal"],["universal","ola","uber","bangalore"]]);