需要更正或建议javascript计算两个日期之间的差异

Question

年龄计算

我从许多网站收集了这个JavaScript;我想知道两个不同日期之间的年龄;
在这个脚本或示例中，我希望显示我的女儿年龄;;一切都很顺利，直到她6个月大，

脚本将年龄四舍五入到上面的数字，即(本例中为一年)，和将显示月份为负数的月份舍入。

如果小于365天，我希望脚本查看年数四舍五入到较低的数字，从少于365天的天数起四舍五入。

<!-- Calculate Age -->
<script type="text/javascript">
var s = '2016-01-31T17:17:28.593Z';
var a = s.split(/[^0-9]/);
var d=new Date (a[0],a[1]-1,a[2],a[3],a[4],a[5] );
var fromDate = new Date(d);
var toDate = new Date();
// current date format as mm-dd-yyyy 
    var Start_Date = new Date(d);
    var sec = Start_Date.getSeconds();
    var min = Start_Date.getMinutes();
    var hr = Start_Date.getHours();
    var dd = Start_Date.getDate();
    var mm = Start_Date.getMonth()+1; //January is 0!
    var yyyy = Start_Date.getFullYear();
	if(dd<10){
			dd='0'+dd
		} 
	if(mm<10){
			mm='0'+mm
		}
	if(hr<10){
			hr='0'+hr
		}
	if(min<10){
			min='0'+min
		}
var Start_Date = dd+'-'+mm+'-'+yyyy+'&nbsp at <span style="direction:ltr; color:red ;font-weight:700;">[&nbsp'+hr+ ":" +min+ ":" +sec+'&nbsp]</span>';
// End date format as mm-dd-yyyy
// Start_Date = str;
var differenceTravel = toDate.getTime() - fromDate.getTime();
// var months = Math.ceil (toDate.getMonth() - fromDate.getMonth() + (12 * (toDate.getFullYear() - 
// 1 day = 86400000,
var Tyears = Math.round(differenceTravel/1000/60/60/24/365);
var Tmonths = Math.round((differenceTravel - (Tyears * 365*60*60*24*1000)) / (1000*60*60*24*30));
var Tdays = Math.round((differenceTravel - (Tyears *60*60*24*365*1000) - (Tmonths *60*60*24*30*1000))/ (86400000));
//
document.writeln('<div style="color:Blue">');
document.writeln('<ul>');
document.writeln('<li><span style="color:Navy">Seba Birthday:&nbsp;</span> ' + Start_Date +'</li>');
document.write('<li><span style="color:MediumVioletRed">Her age is:</span>&nbsp; '+ Tyears +'<span style="color:Green">&nbsp;year &nbsp; and &nbsp; </span>'+ Tmonths +'<span style="color:Green">&nbsp;months &nbsp; and &nbsp;</span>'+ Tdays +'<span style="color:Green">&nbsp;days</span></li>');
document.writeln('</ul></div>');
</script>
<!-- / good -->

Answer 1

如果要舍入，请使用Math。floor，而不是Math.round，它将根据值是<还是>而不是0.5向上或向下舍入。

Answer 2

修改以下三行:

var Tyears = Math.round(differenceTravel/1000/60/60/24/365);
var Tmonths = Math.round((differenceTravel - (Tyears * 365*60*60*24*1000)) / (1000*60*60*24*30));
var Tdays = Math.round((differenceTravel - (Tyears *60*60*24*365*1000) - (Tmonths *60*60*24*30*1000))/ (86400000));

到以下:

var Tyears = Math.floor(differenceTravel/1000/60/60/24/365);
var Tmonths = Math.ceil((differenceTravel - (Tyears * 365*60*60*24*1000)) / (1000*60*60*24*30));
var Tdays = Math.round((differenceTravel - (Tyears *60*60*24*365*1000) - (Tmonths *60*60*24*30*1000))/ (86400000));