我现在使用这个模式
do {
if let jsonResult = try NSJSONSerialization.JSONObjectWithData(data!, options: []) as? NSDictionary {
let valid: Int? = 1
let status: String? = "ok"
if let v = jsonResult["valid"] as? Int, s = jsonResult["status"] as? String {
if v == valid && s == status{
//Do something
}
}
}
这是检验v == 1和s == "ok"的最佳方法吗
或者有可能做一些像这样的答案,它会更好吗?答案(在一行中展开多个可选项)
if let v = jsonResult["valid"] as? Int, s = jsonResult["status"] as? String
where is(v, valid && s, status)
如果您不需要v
和s
在if
的主体内,您可以直接进行比较:
if jsonResult["valid"] as? Int == 1 && jsonResult["status"] as? String == "ok" {
// Do something
}
尝试:
if let v = jsonResult["valid"] as? Int, s = jsonResult["status"] as? String where (v == valid && s == status) {}
你应该试试guard语句像这样
let dict = NSDictionary()
dict.setValue(Int(1), forKey: "one")
dict.setValue("String", forKey: "two")
guard let one = dict["one"] as? Int, two = dict["two"] as? String where one == 1 && two == "String" else {
print ("no")
return
}
print ("one is (one) two is (two)")