JavaScript:遍历多维数组并提取多个搜索值

Question

我想做的事情：

使用多个搜索字符串搜索多维数组。

我目前正在做的事情示例：

var multiArray = [['Apples and pears', 'tuna salad'],['bananas tuna'],['the colour blue']];
var singleArray = [];
var match_array = [];
// Turn multiple arrays into one big one
    for (var i = 0; i < multiArray.length; i++) {
        for (var x = 0; x < multiArray[i].length; x++) {
            singleArray.push(multiArray[i][x]);
    }
}
// Create a new array from matched strings
function find_match(to_match) {
    for (var i in singleArray) {
        if (singleArray[i].indexOf(to_match)!= -1)
        match_array.push(singleArray[i]);
    }
    return (match_array.length === 0 ? null : match_array);
}
// Find matching terms for match_array
find_match('tuna');
find_match('the');
alert(match_array);

JSFiddle演示

问题：

1. 显然，这是一种杂乱无章的方式。这怎么可能流线型(即直接搜索multiArray，而不使用多个find_match功能(？

2. 如何只获得精确的字符串匹配，最好不分解多维数组？

3. 你对搜索海量内容有什么想法多维数组？

Answer 1

你想要这样的东西吗？

var multiArray = [['Foo', 'Bar'],['Foo'],['Bar']];
var singleArray = [];
var match_array = [];
// Turn multiple arrays into one big one
for (var i = 0; i < multiArray.length; i++) {
    for (var x = 0; x < multiArray[i].length; x++) {
        singleArray.push(multiArray[i][x]);
    }
}
// Create a new array from matched strings
function find_match(to_match, where_search) {
    for (var j in where_search) {
        if(where_search[j] instanceof Array){
           find_match(to_match, where_search[j]);
        }else{
            for (var i in to_match) {
                if (where_search[j].indexOf(to_match[i]) ==0 && 
                    where_search[j].length == to_match[i].length)
                    match_array.push(where_search[j]);
            }
        }
    }
    return (where_search.length === 0 ? null : match_array);
}
// Find matching terms for match_array
find_match(['Foo', 'Bar'],multiArray);
alert(match_array);