我正在研究课堂上的一个学习问题,本质上它读取了一个字符串和一个字符。 字符是分隔符。 然后,它将在字符串中搜索分隔符,并创建一个长度与找到分隔符的次数相等的数组。 然后,它将每个字符或字符串分配给数组中自己的位置并返回它。
也许我想多了,但只是不依赖各种字符串方法,而是创建自己的字符串方法。 如何让此方法仅将读取的字符串/字符分配给数组中的一个位置,而不是全部,并阻止它添加不必要的输出? 非常感谢帮助/建议
public static String[] explode(String s, char d){
String []c;
int count = 1;
//checks to see how many times the delimter appears in the string and creates an array of corresponding size
for(int i = 0; i < s.length(); i++){
if(d == s.charAt(i))
count ++;
}
c = new String [count];
//used for checking to make sure the correct number of elements are found
System.out.println(c.length);
//goes through the the input string "s" and checks to see if the delimiter is found
//when it is found it makes c[j] equal to what is found
//once it has cycled through the length of "s" and filled each element for c, it returns the array
for(int i = 0; i < s.length(); i++){
for(int j = 0; j < c.length; j++){
if(d == s.charAt(i))
c[j] += s.substring(i-1);
}
}
//provides output for the array [c] just to verify what was found
for(int y = 0; y < c.length; y++)
System.out.println(c[y]);
return c;
}
public static void main(String [] args){
String test = "a,b,c,d";
char key = ',';
explode(test,key);
}
^The following will output:
4
nulla,b,c,db,c,dc,d
nulla,b,c,db,c,dc,d
nulla,b,c,db,c,dc,d
nulla,b,c,db,c,dc,d
I'm aiming for:
4
a
b
c
d
谢谢
也许你可以尝试这样的事情:
public static void main(String[] args){
explode("a,b,c,d", ',');
}
public static void explode(final String string, final char delimiter){
int length = 1;
for(final char c : string.toCharArray())
if(delimiter == c)
length++;
if(length == 1)
return;
final String[] array = new String[length];
int index, prev = 0, i = 0;
while((index = string.indexOf(delimiter, prev)) > -1){
array[i++] = string.substring(prev, index);
prev = index+1;
}
array[i] = string.substring(prev);
System.out.println(length);
for(final String s : array)
System.out.println(s);
}
上述程序的输出为:
4
a
b
c
d
或者,如果你想使用List<String>
(和Java 8),你可以通过做这样的事情来删除几行:
public static void explode(final String string, final char delimiter){
final List<String> list = new LinkedList<>();
int index, prev = 0;
while((index = string.indexOf(delimiter, prev)) > -1){
list.add(string.substring(prev, index));
prev = index+1;
}
list.add(string.substring(prev));
System.out.println(list.size());
list.forEach(System.out::println);
}