在我的请求AJAX中,在beforesend中我禁用了所有按钮,因为在我看来是更好的安全选择。在成功中,我再次启用所有按钮。但是我的页面中还有许多其他按钮,我需要在成功请求后重新启动默认禁用状态。
是否有一种方法从获取值在发送之前设置并在成功后设置此正确的禁用状态?
因为在我的代码中,我成功启用所有按钮,但我需要完全像以前一样恢复禁用状态请求。
在我的简单代码下面。
$.ajax({
url :"/action/controller.php",
type :"POST",
data : data.serialize()
+ '&'
+ encodeURI('action')
+ '='
+ encodeURI(action)
+ '&'
+ encodeURI('tableid')
+ '='
+ encodeURI(tableid)
+ '&'
+ encodeURI('id')
+ '='
+ encodeURI(id),
beforeSend: function(){
//imgload.fadeIn('slow');
$('button').attr('disabled', true);
//console.log ($('button[name="action"]'));
},
success: function(retorno){
//console.log( retorno );
//msg(retorno, 'info');
datagrid();
$('form').unbind('submit').bind('submit');
$('button').attr('disabled', false);
}
.html:
<button id="formbutton" type="button" data-action="back" data-tableid="<?php echo $tableid; ?>" data-id="<?php echo $id; ?>" class="btn btn-primary" title="Voltar" value="back">
<span class="glyphicon glyphicon-chevron-left"></span>
</button>
<button id="formbutton" type="button" data-action="new" data-tableid="<?php echo $tableid; ?>" data-id="<?php echo $id; ?>" class="btn btn-primary" title="Novo" value="new">
<span class="glyphicon glyphicon-plus-sign"></span> Novo
</button>
<button id="formbutton" type="submit" data-action="save" data-tableid="<?php echo $tableid; ?>" data-id="<?php echo $id; ?>" class="btn btn-primary" title="Salvar" value="save">
<span class="glyphicon glyphicon-saved"></span> Salvar
</button>
<button id="formbutton" type="submit" data-action="delete" data-tableid="<?php echo $tableid; ?>" data-id="<?php echo $id; ?>" class="btn btn-primary" title="Delete" value="delete">
<span class="glyphicon glyphicon-minus-sign"></span> Excluir
</button>
<button id="formbutton" type="submit" data-action="edit" data-tableid="<?php echo $tableid; ?>" data-id="<?php echo $id; ?>" class="btn btn-primary" title="Editar" value="edit">
<span class="glyphicon glyphicon-edit"></span> Editar
</button>
<button id="formbutton" type="submit" data-action="duplicate" data-tableid="<?php echo $tableid; ?>" data-id="<?php echo $id; ?>" class="btn btn-primary" title="Duplicar" value="duplicate">
<span class="glyphicon glyphicon-duplicate"></span> Duplicar
</button>
<button id="formbutton" type="submit" data-action="next" data-tableid="<?php echo $tableid; ?>" data-id="<?php echo $id; ?>" class="btn btn-primary" title="Proximo" value="next">
<span class="glyphicon glyphicon-chevron-right"></span>
</button>
您可以在
刚刚禁用的按钮上添加一个类,并仅禁用已启用的按钮,然后您只需为您的类启用按钮:
beforeSend: function(){
//imgload.fadeIn('slow');
$('button:enabled').addClass('toEnable').attr('disabled', true);
//console.log ($('button[name="action"]'));
},
success: function(retorno){
//console.log( retorno );
//msg(retorno, 'info');
datagrid();
$('form').unbind('submit').bind('submit');
$('button.toEnable').removeClass('toEnable').attr('disabled', false);
}