为什么我无法使用 HttpWebRequest 获取请求？

Question

我想从 https://sprzedajemy.pl/doskonale-dla-pary-planujacej-poszerzenie-rodziny-sprawdz-warszawa-2-1b8e55-nr57347155 那里获取电话号码

电话号码是"保护"，我必须单击"显示号码"才能获得电话请求。在我发送请求之前，我必须从源 data-id="805c74a74f3ea9fe6db5da90d722" 从"显示编号"按钮获取，并使用此令牌发送 POST 作为_rp_offerID。

正确答案是：

<span><strong><a href="tel:[phone]"> 516 000 551</a></strong></span>

我的回答是：

？

我的完整代码：

HttpWebRequest getRequest = (HttpWebRequest)WebRequest.Create("https://sprzedajemy.pl/oferta-dane.telefon");
        getRequest.Method = "POST";
        getRequest.UserAgent = "Mozilla/5.0 (Windows NT 6.2; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/27.0.1453.116 Safari/537.36";
        getRequest.ContentType = "application/x-www-form-urlencoded";
        getRequest.Host = "sprzedajemy.pl";
        getRequest.Referer = url;
        getRequest.Headers.Add("accept-encoding", "gzip, deflate, br");
        getRequest.Headers.Add("accept-language", "pl,en-US;q=0.9,en;q=0.8,ru;q=0.7");
        getRequest.Headers.Add("origin", "https://sprzedajemy.pl");
        getRequest.Headers.Add("X-Requested-With", "XMLHttpRequest");
        var postData = "_rp_offerID=" + itemId;
        var data = Encoding.ASCII.GetBytes(postData);
        getRequest.ContentLength = data.Length;
        using (var stream = getRequest.GetRequestStream())
        {
            stream.Write(data, 0, data.Length);
        }
        var httpResponseP = (HttpWebResponse)getRequest.GetResponse();
        var streamReaderP = new StreamReader(httpResponseP.GetResponseStream());
        string strPhone = streamReaderP.ReadToEnd();
        Console.WriteLine(strPhone);

我不知道我的代码出了什么问题...

如果我将 REST 客户端用于 Chrome

：

POST https://sprzedajemy.pl/oferta-dane.telefon User-Agent: Mozilla/5.0 (Windows NT 6.2; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/27.0.1453.116 Safari/537.36 Content-Type: application/x-www-form-urlencoded Referer: http://sprzedajemy.pl/doskonale-dla-pary-planujacej-poszerzenie-rodziny-sprawdz-warszawa-2-1b8e55-nr57347155 accept-encoding: gzip, deflate, br accept-language: pl,en-US;q=0.9,en;q=0.8,ru;q=0.7 origin: https://sprzedajemy.pl X-Requested-With: XMLHttpRequest Host: sprzedajemy.pl Content-Length: 48

体型数据： _rp_offerID=80e158b0281e04a2102fd7bce6eba0cd3833

答案是正确的

Answer 1

为什么不使用 HttpClient？这要容易得多！检查以下示例：

using System;
using System.Net.Http;
using System.Text;
namespace httpClient
{
    class Program
    {
        static void Main(string[] args)
        {
            using (var client = new HttpClient() {BaseAddress = new Uri("https://sprzedajemy.pl")})
            {
                client.DefaultRequestHeaders.Add("accept-encoding", "gzip, deflate, br");
                client.DefaultRequestHeaders.Add("accept-language", "pl,en-US;q=0.9,en;q=0.8,ru;q=0.7");
                client.DefaultRequestHeaders.Add("origin", "https://sprzedajemy.pl");
                client.DefaultRequestHeaders.Add("X-Requested-With", "XMLHttpRequest");
                var postData = "_rp_offerID=80e158b0281e04a2102fd7bce6eba0cd3833";
                var stringContent = new StringContent(postData, Encoding.Default, "application/x-www-form-urlencoded");
                var result = client.PostAsync("oferta-dane.telefon", stringContent).GetAwaiter().GetResult();
            }
        }
    }
}

我已经测试了这段代码，返回率为 200