弹簧数据 Jpa 查找顶部和查找第一个生成错误 '@P0'附近的语法不正确

Question

我正在使用spring数据JPA 1.8.2并试图获得顶级结果。我正在使用以下方法

LearningSession findTopBySourceAndExternalLmsSessionIdAndCourseCodeAndLearnerEnrollmentEnrollmentStatusOrderByIdAsc(String source, String externalLmsSessionId, String courseCode, String enrollmentStatus);

我也试过删除OrderBy

LearningSession findTopBySourceAndExternalLmsSessionIdAndCourseCodeAndLearnerEnrollmentEnrollmentStatus(String source, String externalLmsSessionId, String courseCode, String enrollmentStatus);

在这两种情况下，hibernate都生成以下查询。所有的都用*。order by learningse0_.id asc

select TOP ?  learningse0_.*
from LearningSession learningse0_ 
left outer join LearnerEnrollment learnerenr1_ on learningse0_.ENROLLMENT_ID=learnerenr1_.id 
where learningse0_.source=?
and learningse0_.externalLmsSessionId=?
and learningse0_.courseCode=?
and learnerenr1_.enrollmentStatus=?

查询是正确的，但是我得到以下异常

Hibernate: select TOP ?  learningse0_.id as id1_47_, learningse0_.brandName as brandNam2_47_, learningse0_.courseApprovalId as courseAp3_47_, learningse0_.courseCode as courseCo4_47_, learningse0_.endTime as endTime5_47_, learningse0_.externalLmsSessionId as external6_47_, learningse0_.externalLmsUrl as external7_47_, learningse0_.isCourseMessageDisplay as isCourse8_47_, learningse0_.LANGUAGE_ID as LANGUAG15_47_, learningse0_.LEARNER_ID as LEARNER16_47_, learningse0_.ENROLLMENT_ID as ENROLLM17_47_, learningse0_.learningSessionGuid as learning9_47_, learningse0_.lmsProvider as lmsProv10_47_, learningse0_.redirectUrl as redirec11_47_, learningse0_.source as source12_47_, learningse0_.startTime as startTi13_47_, learningse0_.uniqueUserGuid as uniqueU14_47_ from LearningSession learningse0_ left outer join LearnerEnrollment learnerenr1_ on learningse0_.ENROLLMENT_ID=learnerenr1_.id where learningse0_.source=? and learningse0_.externalLmsSessionId=? and learningse0_.courseCode=? and learnerenr1_.enrollmentStatus=? order by learningse0_.id asc
13:53:47.686 [main] DEBUG org.hibernate.engine.jdbc.spi.SqlExceptionHelper - could not extract ResultSet [n/a]
com.microsoft.sqlserver.jdbc.SQLServerException: Incorrect syntax near '@P0'          
com.microsoft.sqlserver.jdbc.SQLServerException.makeFromDatabaseError(SQLServerException.java:216) ~[sqljdbc4-4.0.jar:?]

我做错了什么?我尝试了First, Top1, First1，但结果是错误的。请帮助。

谢谢

Answer 1

不确定这是否适用于您，但我遇到了同样的错误，经过大量的挖掘，我发现我在我的JpaVendorAdapter中使用SqlServerDialect，当我将其更改为更具体的SqlServer2012 (SqlServerDialect2012)时，错误消失了:

<bean id="jpaVendorAdapter"
    class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
    <property name="database" value="SQL_SERVER" />
    <property name="databasePlatform" value="org.hibernate.dialect.SQLServer2012Dialect" />
    <property name="showSql" value="true" />
</bean>

Answer 2

我在使用Hibernate 5 + Spring Data时遇到了同样的问题。将Dialect更改为SQLServer2012Dialect对我有效。

公共类SQLServerNativeDialect扩展SQLServer2012Dialect

供参考:https://hibernate.atlassian.net/browse/hhh - 10032

谢谢,