我在数据库中有一个通知表,其中包含属性:timestamp:datetime
和read:boolean
。我想要的是查询和排序我的通知;首先看它们是否被读取,然后看它们获得了哪个时间戳,然后将通知的数量限制为10。
我尝试的查询看起来像这样:
@user.notifications.order_by([[:read,:desc],[:timestamp,:desc]]).limit(10)
这只给了我一个错误,我缩小到证明布尔字段是罪魁祸首。
是否存在按真/假值排序的现有方法,或者我是否应该使用某种自定义字段序列化将true和false转换为1和0 ?
您指定的内容适用于我的Mongoid 2.4.10, mongo 1.3, rails 3.2.3。希望以下内容有助于解决您的问题。
class User
include Mongoid::Document
field :name, type: String
has_many :notifications
end
class Notification
include Mongoid::Document
field :read, type: Boolean
field :timestamp, type: DateTime
belongs_to :user
end
测试/单位/notification_test.rb
require 'test_helper'
class NotificationTest < ActiveSupport::TestCase
def setup
User.delete_all
Notification.delete_all
end
test "order_by boolean" do
@user = User.create(name: 'Gary')
[
[true, 1.day.ago], [false, 2.days.ago], [false, 3.days.ago], [true, 5.days.ago], [false, 8.days.ago], [true, 11.days.ago],
[false, 4.days.ago], [true, 6.days.ago], [true, 7.days.ago], [false, 9.days.ago], [false, 10.days.ago]
].each do |read, timestamp|
@user.notifications << Notification.create(read: read, timestamp: timestamp)
end
assert_equal(1, User.count)
assert_equal(11, Notification.count)
result = @user.notifications.order_by([[:read,:desc],[:timestamp,:desc]]).limit(10).to_a
assert_equal(10, result.size)
result.each do |r|
p [r.read, r.timestamp]
end
end
end
测试输出Run options: --name=test_order_by_boolean
# Running tests:
[true, Mon, 28 May 2012 12:33:49 -0400]
[true, Thu, 24 May 2012 12:33:49 -0400]
[true, Wed, 23 May 2012 12:33:49 -0400]
[true, Tue, 22 May 2012 12:33:49 -0400]
[true, Fri, 18 May 2012 12:33:49 -0400]
[false, Sun, 27 May 2012 12:33:49 -0400]
[false, Sat, 26 May 2012 12:33:49 -0400]
[false, Fri, 25 May 2012 12:33:49 -0400]
[false, Mon, 21 May 2012 12:33:49 -0400]
[false, Sun, 20 May 2012 12:33:49 -0400]
.
Finished tests in 0.023062s, 43.3614 tests/s, 130.0841 assertions/s.
1 tests, 3 assertions, 0 failures, 0 errors, 0 skips