我对命名空间的工作原理感到困惑。 我正在尝试获取ss:Name="Datagrid"
的worksheet
,并从中获取data
节点
name="emailname"
Imports <xmlns:ss="urn:schemas-microsoft-com:office:spreadsheet">
Module Module1
Sub Main()
Dim xmlFile As String = System.AppDomain.CurrentDomain.BaseDirectory & "Datagrid.xml"
Dim root As XElement = XElement.Load(xmlFile)
''select worksheet where ss:Name="Datagrid""
'Dim dg = From item In root .......................
''get data from wokrsheet...table..row...data where = name="emailname" (not ss:name="emailname")
'Dim data = From item In dg .......................
End Sub
End Module
.XML
<?xml version="1.0"?>
<?mso-application progid="Excel.Sheet"?>
<Workbook xmlns="urn:schemas-microsoft-com:office:spreadsheet"
xmlns:o="urn:schemas-microsoft-com:office:office"
xmlns:x="urn:schemas-microsoft-com:office:excel"
xmlns:ss="urn:schemas-microsoft-com:office:spreadsheet"
xmlns:html="http://www.w3.org/TR/REC-html40">
<Worksheet ss:Name="Datagrid">
<Table ss:ExpandedColumnCount="13" ss:ExpandedRowCount="11" x:FullColumns="1"
x:FullRows="1" ss:DefaultRowHeight="15">
<Row ss:Index="3" ss:AutoFitHeight="0">
<Cell Name="emailname">
<Data ss:Type="String">email address</Data>
</Cell>
</Row>
<Row ss:Index="4" ss:AutoFitHeight="0">
<Cell Name="username">
<Data ss:Type="String">user name</Data>
</Cell>
</Row>
</Table>
</Worksheet>
<Worksheet ss:Name="Properties">
<Table ss:ExpandedColumnCount="1" ss:ExpandedRowCount="3" x:FullColumns="1"
x:FullRows="1" ss:DefaultRowHeight="15">
<Row>
<Cell>
<Data ss:Type="Number">1</Data>
</Cell>
</Row>
<Row>
<Cell>
<Data ss:Type="Number">2</Data>
</Cell>
</Row>
<Row>
<Cell>
<Data ss:Type="Number">3</Data>
</Cell>
</Row>
</Table>
</Worksheet>
</Workbook>
在文件顶部声明带有Imports
语句的命名空间。然后,您可以使用<ns:name>
语法引用它们。
所以
Imports <xmlns="urn:schemas-microsoft-com:office:spreadsheet">
Imports <xmlns:o="urn:schemas-microsoft-com:office:office">
Imports <xmlns:x="urn:schemas-microsoft-com:office:excel">
Imports <xmlns:ss="urn:schemas-microsoft-com:office:spreadsheet">
Imports <xmlns:html="http://www.w3.org/TR/REC-html40">
将为您提供由您提供的 XML 定义的命名空间。
现在,您可以访问<Workbook>...<Table>.@x:FullRows
,包括在 LINQ 查询中。
VB.NET 的这些 XML 功能在Microsoft文档中称为轴属性。
我已经将您的XML粘贴到VS2008中,并确定您的问题是XML标签(包括轴属性中的XML标签)区分大小写:
''select worksheet where ss:Name="Datagrid""
'Dim dg = From item In root .......................
Dim dg = root.<Worksheet>.FirstOrDefault(Function(w) w.@ss:Name = "Datagrid")
If dg Is Nothing Then _
Throw New Exception("DataGrid not found")
''get data from wokrsheet...table..row...data where = name="emailname" (not ss:name="emailname")
'Dim data = From item In dg .......................
' Both of the following lines work, but the second answers the question in the title:
'Dim data = dg.<Table>.<Row>.<Cell>.FirstOrDefault(Function(d) d.@Name = "emailname")
Dim data = dg...<Cell>.FirstOrDefault(Function(d) d.@Name = "emailname")
If data Is Nothing Then _
Throw New Exception("emailname not found")
Console.WriteLine(data.<Data>.Value)
若要获得更简洁的语法,建议尝试如下所示的 Linq-to-XML XPath 扩展方法。
更新 #1:如果 XML 文件不包含任何命名空间,则以下代码有效。正在研究考虑命名空间的解决方案。
Dim root = XElement.Load(xmlFile)
Dim data = root.XPathSelectElements("Worksheet[@Name=""Datagrid""]/Table/Row/Cell/Data[@Name=""edata""]")