拍摄照片并将其上传到服务器，无需任何压缩安卓

Question

我正在尝试从设备相机拍摄照片或从图库中获取照片并通过凌空抽射将其上传到服务器一切正常，但图像质量很差

private void dispatchTakePictureIntent()
{
    Intent intent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
    startActivityForResult(intent , CAMERA_REQUEST_CODE);
}
@Override
public void onActivityResult(int requestCode, int resultCode, Intent data { 
    switch (requestCode) {
    case CAMERA_REQUEST_CODE:
    if ( resultCode == RESULT_OK){                 
    Bundle bundle = data.getExtras();
    bitmap = (Bitmap) bundle.get("data");
    ByteArrayOutputStream stream = new ByteArrayOutputStream();
    bitmap.compress(Bitmap.CompressFormat.PNG, 100, stream);                    
}
break;

和获取参数方法：

    byte[] a = convertBitmapToByteArrayUncompressed(bitmap);
    params.put("img" , Base64.encodeToString(a , Base64.DEFAULT));
public static byte[] convertBitmapToByteArrayUncompressed(Bitmap bitmap){
    ByteBuffer byteBuffer = ByteBuffer.allocate(bitmap.getByteCount());
    bitmap.copyPixelsToBuffer(byteBuffer);
    byteBuffer.rewind();
    return byteBuffer.array();
}

Answer 1

来自 Naugat 拍照会有所不同。

创建图像文件拳头：

String mCurrentPhotoPath;
private File createImageFile() throws IOException {
    // Create an image file name
    String timeStamp = new SimpleDateFormat("yyyyMMdd_HHmmss").format(new Date());
    String imageFileName = "JPEG_" + timeStamp + "_";
    File storageDir = getExternalFilesDir(Environment.DIRECTORY_PICTURES);
    File image = File.createTempFile(
        imageFileName,  /* prefix */
        ".jpg",         /* suffix */
        storageDir      /* directory */
    );
    // Save a file: path for use with ACTION_VIEW intents
    mCurrentPhotoPath = image.getAbsolutePath();
    return image;
}

然后派发拍照意图

static final int REQUEST_TAKE_PHOTO = 1;
private void dispatchTakePictureIntent() {
    Intent takePictureIntent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
    // Ensure that there's a camera activity to handle the intent
    if (takePictureIntent.resolveActivity(getPackageManager()) != null) {
        // Create the File where the photo should go
        File photoFile = null;
        try {
            photoFile = createImageFile();
        } catch (IOException ex) {
            // Error occurred while creating the File
            ...
        }
        // Continue only if the File was successfully created
        if (photoFile != null) {
            Uri photoURI = FileProvider.getUriForFile(this,
                                                  "com.example.android.fileprovider",
                                                  photoFile);
            takePictureIntent.putExtra(MediaStore.EXTRA_OUTPUT, photoURI);
            startActivityForResult(takePictureIntent, REQUEST_TAKE_PHOTO);
        }
    }
}

在活动结果中，检查RESULT_OK是否成功捕获。

if (requestCode == REQUEST_TAKE_PHOTO && resultCode == Activity.RESULT_OK)

您已经获得了图像路径。现在使用mCurrentPhotoPath上传过程。

此外，您需要实现文件提供程序。

在清单中添加以下内容：

<application>
   ...
   <provider
        android:name="android.support.v4.content.FileProvider"
        android:authorities="com.example.android.fileprovider"
        android:exported="false"
        android:grantUriPermissions="true">
        <meta-data
            android:name="android.support.FILE_PROVIDER_PATHS"
            android:resource="@xml/file_paths"></meta-data>
    </provider>
    ...
</application>

在资源目录中的 XML 中并添加以下内容：

<?xml version="1.0" encoding="utf-8"?>
<paths xmlns:android="http://schemas.android.com/apk/res/android">
    <external-path name="my_images" path="Android/data/com.example.package.name/files/Pictures" />
</paths>

现在，您将从相机获得全尺寸图像。

来源： https://developer.android.com/training/camera/photobasics.html

Answer 2

您应该必须使用多部分实体来发送图像而无需压缩。 使用多部分实体，您的图像质量也将得到保持。请按照此操作使用凌空抽射发送图像

public class MultipartReq extends JsonObjectRequest {
    private static final String FILE_PART_NAME = "file";
    private static final String STRING_PART_NAME = "text";
    private final File mFilePart;
    //private final String mStringPart;

    MultipartEntityBuilder entityBuilder = MultipartEntityBuilder.create();
    HttpEntity httpEntity;
    Context context;
    private Map<String, String> params;
    public MultipartReq(Context context, int method, String url, JSONObject jsonRequest, Response.Listener<JSONObject> listener, Response.ErrorListener errorListener, File file, Map<String, String> params) {
        super(method, url, jsonRequest, listener, errorListener);
        this.context = context;
        mFilePart = file;
        entityBuilder.setMode(HttpMultipartMode.BROWSER_COMPATIBLE);    
        this.params = params;
        buildMultipartEntity();
        httpEntity = entityBuilder.build();
    }

    private void buildMultipartEntity() {
        try {
            if (mFilePart.exists()) {                                           entityBuilder.addBinaryBody(FILE_PART_NAME, mFilePart, ContentType.create(mimeType), mFilePart.getName());
                }
                try {
                    if(!params.isEmpty()){
                        for (String key: params.keySet()){
                             entityBuilder.addPart(key, new StringBody(params.get(key),ContentType.TEXT_PLAIN));
                        }
                    }
                } catch (Exception e) {
                    VolleyLog.e("UnsupportedEncodingException");
                }

            } else {
                ShowLog.e("no such file");
            }
        } catch (Exception e) {
            ShowLog.e("UnsupportedEncodingException");
        }
    }
    @Override
    public Map<String, String> getHeaders() throws AuthFailureError {
        HashMap<String, String> params = new HashMap<String, String>();
        return params;
    }

    @Override
    public String getBodyContentType() {
        return httpEntity.getContentType().getValue();
    }
    @Override
    public byte[] getBody() {
        ByteArrayOutputStream bos = new ByteArrayOutputStream();
        try {
            httpEntity.writeTo(bos);
        } catch (IOException e) {
            VolleyLog.e("IOException writing to ByteArrayOutputStream");
        }
        return bos.toByteArray();
    }

    @Override
    protected void deliverResponse(JSONObject response) {
        super.deliverResponse(response);
    }
}

Answer 3

使用getParcelableExtra()，而不是getExtras()用于小尺寸图像。

Bitmap bitmap = (Bitmap) intent.getParcelableExtra("data");

如果图像太大，则必须压缩它们并发送到其他活动。然后，您可以获取压缩的位图并在第二个活动中将其解压缩。尝试下面的代码。

第一次活动

Intent intent = new Intent(this, SecondActivity.class);
ByteArrayOutputStream stream = new ByteArrayOutputStream();
bitmap.compress(Bitmap.CompressFormat.JPG, 100, stream);
byte[] bytes = stream.toByteArray(); 
intent.putExtra("bitmap",bytes);

第二次活动

byte[] bytes = getIntent().getByteArrayExtra("bitmap");
Bitmap bitmap = BitmapFactory.decodeByteArray(bytes, 0, bytes.length);