如何在 AngularJS 中以动态字符串的形式调用函数?

Question

如何在ng-click?中使用function assigned variable？我在下面尝试了三种方法，但这也不起作用。

你能告诉我是否有可能吗???如果是，那怎么做？

var app = angular.module("app", []);
app.controller("name", function($scope) {
$scope.showname = function()
{
alert("Ramesh");
}

$scope.variable1 = $scope.showname;

$scope.variable2 = "showname()";
});

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-app="app" ng-controller="name">
<button type="button" ng-click="variable1" tabindex="10003" >Not working 1 </button>
<button type="button" ng-click="$scope[variable2]()" tabindex="10003" >Not working 2 </button>
<button type="button"  ng-click="variable2" tabindex="10003" >Not working 3 </button>
<button type="button" ng-click="showname()" tabindex="10003"> working </button>
</div>

Answer 1

您可以使用$scope.$eval方法并像variable2()一样调用该函数。

$eval方法不计算 JavaScript;它们只评估AngularJS表达式。

另外，对于以下行

$scope.variable1 = $scope.showname;

您只是保留对showname函数的引用。你必须调用它

<button type="button" ng-click="variable1()" tabindex="10003" >Not working 1 </button>

var app = angular.module("app", []);
app.controller("name", function($scope) {
$scope.showname = function()
{
alert("Ramesh");
}

$scope.variable1 = $scope.showname;

$scope.variable2 = $scope.$eval("showname");
});

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-app="app" ng-controller="name">
<button type="button" ng-click="variable1()" tabindex="10003" >Not working 1 </button>
<button type="button" ng-click="variable2()" tabindex="10003" >Not working 2 </button>
<button type="button"  ng-click="variable2()" tabindex="10003" >Not working 3 </button>
<button type="button" ng-click="showname()" tabindex="10003"> working </button>
</div>

Answer 2

尝试：

<button type="button" ng-click="variable1()" tabindex="10003" >Now it'll work 1 </button>

工作 plunkr

Answer 3

$scope.showname具有函数引用。因此，只需将其分配给您的变量，例如

$scope.variable1 = $scope.showname

然后像valiable1()一样点击 ng

var app = angular.module("app", []);
app.controller("name", function($scope) {
$scope.showname = function()
{
alert("Ramesh");
}

$scope.variable1 = $scope.showname;

$scope.variable2 =  $scope.showname;
});

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-app="app" ng-controller="name">
<button type="button" ng-click="variable1()" tabindex="10003" >Not working 1 </button>
<button type="button" ng-click="variable2()" tabindex="10003" >Not working 2 </button>
<button type="button"  ng-click="variable1()" tabindex="10003" >Not working 3 </button>
<button type="button" ng-click="showname()" tabindex="10003"> working </button>
</div>

Answer 4

不使用$scope，使用this关键字：

错误

<button type="button" ng-click="$scope[variable2]()" tabindex="10003" >
Not working 2 
</button>

改为使用：

<button type="button" ng-click="this[variable2]()" tabindex="10003" >
working
</button>

可以使用标识符this访问上下文对象。

更多信息，请参见 AngularJS 开发者指南 - 表达式上下文。