如果使用Junit的条件，如何模拟

Question

我正在尝试使用Mockito模拟方法。如果使用Mockito，如何模拟条件？

这是我的代码

@Override public RemedyWrapperOutput createmedyticket（RemedyWrapperInput RemedyWrapperInput）抛出异常{

    logger.info("Inside createRemedyTicket");
    RemedyWrapperOutput result = new RemedyWrapperOutput();
    final RemedyRecord remData = remedyDao.getByApiAndTitle(remedyWrapperInput.getInstance(),
            remedyWrapperInput.getTitle());
    /**
     * if no records exists in the DB or if the RemedyStatus is
     * CLOSED/RESOLVED/CANCELLED, we create a new ticket.
     */
    if (remData == null ||remData.getStatus().equals(RemedyStatus.RESOLVED)
            || remData.getStatus().equals(RemedyStatus.CLOSED)|| remData.getStatus().equals(RemedyStatus.CANCELLED)) {
        createRemedyTicket(remedyWrapperInput, result);
    } else {
        /* If record exists check if its within duration */
        /**
         * If not within time range create a ticket if New and Assigned
         * status. For all other status stop processing.
         */
        if (!checkIfInTimeRange(remData.getCreationDateTime())) {
            if (remData.getStatus() != null && (remData.getStatus().equals(RemedyStatus.NEW)
                          || remData.getStatus().equals(RemedyStatus.ASSIGNED)
                          || remData.getStatus().equals(RemedyStatus.PENDING)
                          || remData.getStatus().equals(RemedyStatus.IN_PROGRESS))) {
                   int id = remedyDao.create(createRemedyInput(remedyWrapperInput, remData));
                   callRemedyRestApi(remedyWrapperInput, result, id);
                   result.setMessage("Remedy request submitted");
            }  
        } else {
            result.setMessage("A request of this category has already been logged inside specified time range.");
        }
        // Update the last update time to current time
        remedyDao.update(remData);
    }
    return result;
}

Answer 1

我想您想查看要模拟的方法。而不是该方法的内容。让我用一个示例解释。这是我想测试的简单课程：

package com.diffblue.javademo;
public class ClassToTest {
  private boolean beenChecked = false;
  private SomeDAO someDAO = new SomeDAO();
  public void checkActive(int id) {
    if (someDAO.isActive(id)) {
      beenChecked = true;
    }
  }
  public boolean getBeenChecked() {
    return beenChecked;
  }
}

它打电话给我想模拟的某种程度：

package com.diffblue.javademo;
public class SomeDAO {
  public  boolean isActive(int id) {
    if (id < 5) {
      return true;
    }
    return false;
  }
}

当我创建一个测试案例时，我会考虑我要测试的checkActive路径，然后从isActive中选择一个可以锻炼该路径的答案。例如：

package com.diffblue.javademo;
import org.junit.Assert;
import org.junit.Test;
import org.mockito.Matchers;
import org.powermock.api.mockito.PowerMockito;
import org.powermock.core.classloader.annotations.PrepareForTest;
import static org.mockito.Mockito.when;
public class ClassToTestTest {
  /**
   * Test the positive side of the if statement in checkActive
   */
  @PrepareForTest({SomeDAO.class})
  @Test
  public void positiveTest() throws Exception {
    // Arrange
    ClassToTest objectUnderTest = new ClassToTest();
    SomeDAO someDAO = PowerMockito.mock(SomeDAO.class);
    when(someDAO.isActive(Matchers.anyInt())).thenReturn(true);
    int activeId = 3;
    // Act
    objectUnderTest.checkActive(activeId);
    // Assert
    Assert.assertTrue(objectUnderTest.getBeenChecked());
  }
}

在这种情况下，我检查了IF语句（SomeDao第6行）为真的路径。因此，我没有嘲笑IF语句，但是我通过仔细选择Mockito给出的返回值强制了特定的代码路径。