YouTube API最受欢迎的YouTube视频

Question

我正在尝试使用Python获取流行的YouTube视频数据。虽然我可以成功下载数据，但我无法将其存储或以CSV格式保存。这是我使用的代码：

# -*- coding: utf-8 -*-
import os
import google.oauth2.credentials
import google_auth_oauthlib.flow
from googleapiclient.discovery import build
from googleapiclient.errors import HttpError
from google_auth_oauthlib.flow import InstalledAppFlow

CLIENT_SECRETS_FILE = "client_secret.json"

SCOPES = ['https://www.googleapis.com/auth/youtube.force-ssl']
API_SERVICE_NAME = 'youtube'
API_VERSION = 'v3'
def get_authenticated_service():
  flow = InstalledAppFlow.from_client_secrets_file(CLIENT_SECRETS_FILE, SCOPES)
  credentials = flow.run_console()
  return build(API_SERVICE_NAME, API_VERSION, credentials = credentials)
def print_response(response):
  print(response)

def build_resource(properties):
  resource = {}
  for p in properties:
   
    prop_array = p.split('.')
    ref = resource
    for pa in range(0, len(prop_array)):
      is_array = False
      key = prop_array[pa]
      # For properties that have array values, convert a name like
      # "snippet.tags[]" to snippet.tags, and set a flag to handle
      # the value as an array.
      if key[-2:] == '[]':
        key = key[0:len(key)-2:]
        is_array = True
      if pa == (len(prop_array) - 1):
        # Leave properties without values out of inserted resource.
        if properties[p]:
          if is_array:
            ref[key] = properties[p].split(',')
          else:
            ref[key] = properties[p]
      elif key not in ref:
        # For example, the property is "snippet.title", but the resource does
        # not yet have a "snippet" object. Create the snippet object here.
        # Setting "ref = ref[key]" means that in the next time through the
        # "for pa in range ..." loop, we will be setting a property in the
        # resource's "snippet" object.
        ref[key] = {}
        ref = ref[key]
      else:
        # For example, the property is "snippet.description", and the resource
        # already has a "snippet" object.
        ref = ref[key]
  return resource
# Remove keyword arguments that are not set
def remove_empty_kwargs(**kwargs):
  good_kwargs = {}
  if kwargs is not None:
    for key, value in kwargs.iteritems():
      if value:
        good_kwargs[key] = value
  return good_kwargs
def videos_list_most_popular(client, **kwargs):
  # See full sample for function
  kwargs = remove_empty_kwargs(**kwargs)
  response = client.videos().list(
    **kwargs
  ).execute()
  return print_response(response)

if __name__ == '__main__':
  # When running locally, disable OAuthlib's HTTPs verification. When
  # running in production *do not* leave this option enabled.
  os.environ['OAUTHLIB_INSECURE_TRANSPORT'] = '1'
  client = get_authenticated_service()
  
  videos_list_most_popular(client,
    part='snippet,contentDetails,statistics',
    chart='mostPopular',
    regionCode='US',
    videoCategoryId='')

如何将结果保存在CSV格式中？我尝试了以下代码，但有一个错误：

data = json.loads(str(响应，'utf-8'((

名称：名称"响应"未定义

Answer 1

nameError表示变量response不在您正在运行它的上下文中。我不知道您在代码中放置该行的位置，但是您调用videos_list_most_popular函数，该功能不会返回任何数据。

videos_list_most_popular返回print_response功能的结果。但是，由于该功能只会打印响应，并且实际上没有返回任何内容，它将返回None，然后下方下方执行videos_list_most_popular，结果将无。

，它也会消失，因为您没有将该功能的结果分配给任何东西(看起来像：response = videos_list_most_popular(...)(。

您将需要更改videos_list_most_popular，因此它返回response，然后像上述一样分配返回值。然后，您可以执行您写的行。