根据数组中的值拆分数组

Question

我有一个这样的数组

var aaa = [
  [value1,value2],[0,0]],
  [[value3,value4],[0,1]],
  [[value5,value6],[1,0]],
  [[value7,value8],[0,2]],
  [[value9,value10],[1,1]],
  [value11,value12],[2,0]]
];

我想根据[0,1], [0,2]等值将此数组拆分为多个数组

。

array1 = [[value1,value2],[value3,value4],[value7,value8]];
array2 = [[value5,value6],[value9,value10]];
array3 = [[value11,value12]];

Answer 1

使用

var aaa = [
[['value1','value2'],[0,1]],
[['value3','value4'],[0,2]],
[['value5','value6'],[1,0]],
[['value7','value8'],[0,3]],
[['value9','value10'],[1,1]],
[['value11','value12'],[2,0]]];
var result = {};
for (var i = 0; i < aaa.length; i += 1) {
    if (!result[aaa[i][1][0]]) {
        result[aaa[i][1][0]] = [];
    }
    result[aaa[i][1][0]].push(aaa[i][0]);
}

之后

:

result[0]; //[[value1,value2],[value3,value4],[value7,value8]];
result[1]; //[[value5,value6],[value9,value10]];
result[2]; //[[value5,value6],[value9,value10]];

Answer 2

假设:

[['value1','value2'],[0,1]]

在这个例子中:告诉该值必须存储在哪个数组中。

下面的代码将完成以下工作:

var aaa = [
    [['value1','value2'],[0,1]],
    [['value3','value4'],[0,2]],
    [['value5','value6'],[1,0]],
    [['value7','value8'],[0,3]],
    [['value9','value10'],[1,1]],
    [['value11','value12'],[2,0]]
];
var arr_result = new Array();
for (var k in aaa) {
    if (arr_result[aaa[k][1][0]] == undefined) {
        arr_result[aaa[k][1][0]] = new Array();
    }
    arr_result[aaa[k][1][0]][aaa[k][1][1]] = aaa[k][0];
}

警告:这可能会让单元格为空，就像在这个例子中，没有[0,0]单元格