在Python中，对于以下嵌套的else-if链，是否有更优雅的解决方案？
if interval == 1:
a += 1
else:
if interval == 2:
b += 1
else:
if interval == 3:
c += 1
else:
if interval == 4:
d += 1
else:
if interval == 5:
e += 1
else:
if interval == 6:
f += 1
if interval == 1:
a += 1
elif interval == 2:
b += 1
elif interval == 3:
c += 1
elif interval == 4:
d += 1
elif interval == 5:
e += 1
elif interval == 6:
f += 1
当然，如果你能提取a。。f输入字典，如：
state = {"a": 0, "b": 0, "c": 0, "d": 0, "e": 0, "f": 0}
你可以做
interval_to_state = {1: "a", 2: "b", 3: "c", 4: "d", 5: "e", 6: "f"}
state[interval_to_state[interval]] += 1
使用list而不是多个变量：
# a b c d e f # Index 0 are unused.
acc = [0, 0, 0, 0, 0, 0, 0] # OR [0] * 7
if 1 <= interval <= 7:
acc[interval] += 1
# OR acc[interval - 1] += 1
# If you don't want to waste a slot in the list.
我建议使用带有反向查找的字典，比如这个
values = {name: 0 for name in "abcdef"}
indexes = {idx: name for idx, name in enumerate("abcdef", 1)}
values[indexes[interval]] += 1