c-LinkedList在节点中输入字符串并打印列表

Question

我正试图使用此示例在函数中实现一个链表：http://www.sanfoundry.com/c-program-create-linked-list-display-elements/

向下滚动到评论：

   /** HERE. i don't want the "press 0 to exit",
    * i want to take the new message from global var. 
    * then enter into a new node of the linked list.                
    **/

我的问题是我错误地实现了我的代码，但不知道如何解决这个问题。我想我需要一个循环退出策略，但我正在为如何退出而挣扎？

/**whenever i have a new message, 
this global variable copies that message**/
char msg[30]; 
struct node{        
   char num[30]; 
   struct node *ptr;
   };
typedef struct node NODE; //call struct NODE
NODE *head, *first, *temp = 0; //initialize head, temp value to 0 and first
void function(
    //if my message is available, then...
    if(strlen(msg)!=0) {

    while (choice){ //while true
        head  = (NODE *)malloc(sizeof(NODE));
        //i copy the new string from the global variable declared above into
        //the linked list....or that is what i am attempting to do
        strcpy(head->num,msg);
        printf("%sn",s);
        if (first != 0){ 
                temp->ptr = head;
                temp = head;
            }
        else{
                first = temp = head;
            }
            i++;

        /** HERE. i don't want the "press 0 to exit",
        * i want to take the new message from global var. 
        * then enter into a new node of the linked list.                
        **/
        choice=0;
    }
    temp->ptr = 0;
    /*  reset temp to the beginning */
    temp = first;
    while (temp != 0){
        printf("%sn", temp->num);
        count++;
        temp = temp -> ptr;
        }
        printf("No. of nodes in the list = %dn", count);

    }}

字符串1:上的输出

 string1

新字符串2:上的输出

 string2

基本上，在每个新字符串上，不断添加到链接列表中并打印整个列表：

 string1
 string2
 ...

请求任何帮助。

Answer 1

void function(node*head)
{
  struct node* head = head;
   while(NULL != head) {
       printf(num);
       head = head->ptr; 
   }
}

这将打印所有内容。要把它们放进去，你需要这样的东西：

struct node* head = NULL;
void putMsg()
{
   if (NULL == head)
   {
       head  = (node *)malloc(sizeof(NODE));
       temp = head;
   }
   else
   {
      temp2 = (node *)malloc(sizeof(NODE));
      temp->ptr = temp2;
      temp = temp->ptr;
   }
   char message[30];
   scanf("%s", message);
   strcpy(head->num, message);
}

请声明所有变量。这个解决方案并不精确，但至少会引导你。