打印数字图像数组

Question

public class Tester2 {
    public static void main(String[] args) {
        int[][] image = {{0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0},
                         {0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0},
                         {0, 0, 5, 5, 5, 5, 5, 5, 5, 5, 0, 0},
                         {0, 0, 5, 5, 5, 5, 5, 5, 5, 5, 0, 0},
                         {0, 0, 5, 5, 5, 5, 5, 5, 5, 5, 0, 0},
                         {0, 0, 5, 5, 5, 5, 5, 5, 5, 5, 0, 0},
                         {0, 0, 5, 5, 5, 5, 5, 5, 5, 5, 0, 0},
                         {0, 0, 5, 5, 5, 5, 5, 5, 5, 5, 0, 0},
                         {0, 0, 5, 5, 5, 5, 5, 5, 5, 5, 0, 0},
                         {0, 0, 5, 5, 5, 5, 5, 5, 5, 5, 0, 0},
                         {0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0},
                         {0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0}};
        // assume a rectangular image
        int[][] smooth = new int[image.length][image[0].length];
        int sum = 0;
        int col = 0;
        // Compute the smoothed value for non-edge locations in the image.
        for (int row = 1; row < image.length - 1; row++) {
            for (col = 1; col < image[row].length - 1; col++) {
                sum = image[row - 1][col - 1] + image[row - 1][col] + image[row - 1][col + 1] + 
                      image[row][col - 1] + image[row][col] + image[row][col + 1] + 
                      image[row + 1][col - 1] + image[row + 1][col] + image[row + 1][col + 1];
            }
            smooth[row][col] = sum / 9;
        }
        // write out the input
        for (int row = 0; row < image.length; row++) {
            for (int col1 = 0; col1 < image[row].length; col1++) {
                System.out.print(image[row][col1] + " ");
            }
            System.out.println();
        }
        for (int row = 0; row < image.length; row++) {
            for (int col1 = 0; col1 < image[row].length; col1++) {
                System.out.print(image[row][col1] + " ");
            }
            System.out.println();
        }
    }
}

我想打印新数组。新数组是由以下方式创建的：

sum = image[row-1][col-1] + image[row-1][col] + image[row-1][col+1] + 
       image[row][col-1] + image[row][col] + image[row][col+1] + 
       image[row+1][col-1] + image[row+1][col] + image[row+1][col+1]

我该怎么做才能打印出新数组？

Answer 1

看起来您正在打印两次原始数组，而您只需要更改第二个即可打印出新数组，而将image更改为 smooth：

for ( int row=0; row < smooth.length; row++ )
{
  for ( int col1=0; col1 < smooth[row].length; col1++ )
    System.out.print( smooth[row][col1] + " ");
  System.out.println();
}

Answer 2

旁边的事实是，您要像hew Wolff所建议的那样打印图像数组，还应纠正您的算法以计算光滑数组的每个像素：

    for (int row = 1; row < image.length - 1; row++) {
        for (col = 1; col < image[row].length - 1; col++) {
            sum = image[row - 1][col - 1] + image[row - 1][col] + image[row - 1][col + 1] + 
                  image[row][col - 1] + image[row][col] + image[row][col + 1] + 
                  image[row + 1][col - 1] + image[row + 1][col] + image[row + 1][col + 1];
            smooth[row][col] = sum / 9;
        }
    }