我需要按照这种格式在 android 中的编辑文本中格式化电话号码(222) 222-2222 ext222222我创建了一个为我执行自动格式化的观察程序。观察程序工作正常，并正确设置电话号码的格式。我唯一的问题是，当有人手动转到输入的手机中的其他位置并开始删除或添加号码时，自动格式化不起作用。任何想法如何处理这个问题。以下是我当前的观察者的样子：
editText.addTextChangedListener(object : TextWatcher {
override fun onTextChanged(s: CharSequence, start: Int, before: Int, count: Int) {}
override fun beforeTextChanged(s: CharSequence, start: Int, count: Int, after: Int) {}
override fun afterTextChanged(s: Editable) {
val text = editText.text.toString()
val textLength = editText.text.length
if (text.endsWith("-") || text.endsWith(" ")) {
return
}
if (textLength == 1) {
if (!text.contains("(")) {
editText.setText(StringBuilder(text).insert(text.length - 1, "(").toString())
editText.setSelection(editText.text.length)
}
} else if (textLength == 5) {
if (!text.contains(")")) {
editText.setText(StringBuilder(text).insert(text.length - 1, ")").toString())
editText.setSelection(editText.text.length)
}
} else if (textLength == 6) {
editText.setText(StringBuilder(text).insert(text.length - 1, " ").toString())
editText.setSelection(editText.text.length)
} else if (textLength == 10) {
if (!text.contains("-")) {
editText.setText(StringBuilder(text).insert(text.length - 1, "-").toString())
editText.setSelection(editText.text.length)
}
} else if (textLength == 15) {
if (text.contains("-")) {
editText.setText(StringBuilder(text).insert(text.length - 1, " ext").toString())
editText.setSelection(editText.text.length)
}
}
}
})
如果一切都取决于我，这就是我如何处理的（见行间评论）。这仅适用于电话号码格式，假设它是最多 10 位数字的区域号码：
phoneNumber.addTextChangedListener(new TextWatcher() {
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
}
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
}
@Override
public void afterTextChanged(Editable s) {
/* Let me prepare a StringBuilder to hold all digits of the edit text */
StringBuilder digits = new StringBuilder();
/* this is the phone StringBuilder that will hold the phone number */
StringBuilder phone = new StringBuilder();
/* let's take all characters from the edit text */
char[] chars = phoneNumber.getText().toString().toCharArray();
/* a loop to extract all digits */
for (int x = 0; x < chars.length; x++) {
if (Character.isDigit(chars[x])) {
/* if its a digit append to digits string builder */
digits.append(chars[x]);
}
}
if (digits.toString().length() >=3) {
/* our phone formatting starts at the third character and starts with the country code*/
String countryCode = new String();
/* we build the country code */
countryCode += "(" + digits.toString().substring(0, 3) + ") ";
/** and we append it to phone string builder **/
phone.append(countryCode);
/** if digits are more than or just 6, that means we already have our state code/region code **/
if (digits.toString().length()>=6)
{
String regionCode=new String();
/** we build the state/region code **/
regionCode+=digits.toString().substring(3,6)+"-";
/** we append the region code to phone **/
phone.append(regionCode);
/** the phone number will not go over 12 digits if ten, set the limit to ten digits**/
if (digits.toString().length()>=10)
{
phone.append(digits.toString().substring(6,10));
}else
{
phone.append(digits.toString().substring(6));
}
}else
{
phone.append(digits.toString().substring(3));
}
/** remove the watcher so you can not capture the affectation you are going to make, to avoid infinite loop on text change **/
phoneNumber.removeTextChangedListener(this);
/** set the new text to the EditText **/
phoneNumber.setText(phone.toString());
/** bring the cursor to the end of input **/
phoneNumber.setSelection(phoneNumber.getText().toString().length());
/* bring back the watcher and go on listening to change events */
phoneNumber.addTextChangedListener(this);
} else {
return;
}
}
});
每次用户更改 EditText 的值时，此代码都会重新格式化电话号码。我自己测试过它，它可以工作并且不会崩溃。你可以测试。
编辑：这是一个java代码，但我认为你可以很容易地将其重写为Kotlin。
应删除观察程序以避免多次触发afterTextChanged，并在设置方法文本后立即还原它。
editText.addTextChangedListener(object : TextWatcher {
override fun onTextChanged(s: CharSequence, start: Int, before: Int, count: Int) {}
override fun beforeTextChanged(s: CharSequence, start: Int, count: Int, after: Int) {}
override fun afterTextChanged(editable: Editable) {
val text = editText.text.toString()
val textLength = editText.text.length
if (text.endsWith("-") || text.endsWith(" ")) {
return
}
if (textLength == 1) {
if (!text.contains("(")) {
setText(StringBuilder(text).insert(text.length - 1, "(").toString())
}
} else if (textLength == 5) {
if (!text.contains(")")) {
setText(StringBuilder(text).insert(text.length - 1, ")").toString())
}
} else if (textLength == 6) {
setText(StringBuilder(text).insert(text.length - 1, " ").toString())
} else if (textLength == 10) {
if (!text.contains("-")) {
setText(StringBuilder(text).insert(text.length - 1, "-").toString())
}
} else if (textLength == 15) {
if (text.contains("-")) {
setText(StringBuilder(text).insert(text.length - 1, " ext").toString())
}
}
}
private fun setText(text: String){
editText.removeTextChangedListener(this)
editText.editableText.replace(0, editText.text.length, text)
editText.setSelection(text.length)
editText.addTextChangedListener(this)
}
})
这些更改后，它工作正常，但它在ext部分崩溃（与您的问题无关）。或者，您可以使用libphonenumber AsYouType功能来保存一些工作
此代码将解决在中间添加破折号后后返回按钮的问题
editText.addTextChangedListener(object :
TextWatcher {
var isBackspaceClicked = false
override fun beforeTextChanged(p0: CharSequence?, start: Int, count: Int, after: Int) {
isBackspaceClicked = after < count
}
override fun onTextChanged(p0: CharSequence?, p1: Int, p2: Int, p3: Int) { }
override fun afterTextChanged(s: Editable?) {
if (!isBackspaceClicked){
val digits = StringBuilder()
val phone = StringBuilder()
val chars: CharArray = editText!!.text.toString().toCharArray()
for (x in chars.indices) {
if (Character.isDigit(chars[x])) {
digits.append(chars[x])
}
}
if (digits.toString().length >= 3) {
var countryCode = String()
countryCode += "" + digits.toString().substring(0, 3) + "-"
phone.append(countryCode)
if (digits.toString().length >= 6) {
var regionCode = String()
regionCode += digits.toString().substring(3, 6) + "-"
phone.append(regionCode)
if (digits.toString().length >= 10) {
phone.append(digits.toString().substring(6, 10))
} else {
phone.append(digits.toString().substring(6))
}
} else {
phone.append(digits.toString().substring(3))
}
editText!!.removeTextChangedListener(this)
editText!!.setText(phone.toString())
editText!!.setSelection(tilPhoneNumber.editText!!.getText().toString().length)
editText!!.addTextChangedListener(
this
)
} else {
return
}
}`enter code here`
}
})