使两个函数在同一行上输出它们的输出

Question

我正在制作一个解释器，我有一个名为parse()的函数。parse函数返回一些输出

我正在制作一个命令，它在同一行打印两个命令的输出，而不是在单独的行上。

我有以下代码:

def print_command2(command):
    command = command.split("_") # The underscore separates the two commands
    command[0] = command[0].strip("! ") # The command is !
    print(parse(command[0])), # This should print the output of the first command
    print(parse(command[1])) # And this should print the second

我输入了下面的命令来测试它:

! p Hello_p World

(p相当于Python的print命令。)但是它输出如下内容:

Hello
World

我想让它打印这个:

HelloWorld

怎么了?

---

编辑:这个问题的答案打印如下:

Hello
World

所以它不能正常工作

编辑:这是parse函数。请不要介意这些可怕的代码。

def parse(command):
    """Parses the commands."""
    if ';' in command:
        commands = command.split(";")
        for i in commands:
            parse(i)
    if 'n' in command:
        commands = command.split('n')
        for i in commands:
            parse(i)
    elif command.startswith("q"):
        quine(command)
    elif command.startswith("p "):
        print_command(command)
    elif command.startswith("! "):
        print_command2(command)
    elif command.startswith("l "):
        try:
            loopAmount = re.sub("D", "", command)
            lst = command.split(loopAmount)
            strCommand = lst[1]
            strCommand = strCommand[1:]
            loop(strCommand, loopAmount)
        except IndexError as error:
            print("Error: Can't put numbers in loop")
    elif '+' in command:
        print (add(command))
    elif '-' in command:
        print (subtract(command))
    elif '*' in command:
        print (multiply(command))
    elif '/' in command:
        print (divide(command))
    elif '%' in command:
        print (modulus(command))
    elif '=' in command:
        lst = command.split('=')
        lst[0].replace(" ", "")
        lst[1].replace(" ", "")
        stackNum = ''.join(lst[1])
        putOnStack(stackNum, lst[0])
    elif command.startswith("run "):
        command = command.replace(" ", "")
        command = command.split("run")
        run(command[1])
    elif command.startswith('#'):
        pass
    elif command.startswith('? '):
        stackNum = command[2]
        text = input("input> ")
        putOnStack(text, stackNum)
    elif command.startswith('@ '):
        stackNum = command[2]
        print(''.join(stack[int(stackNum)]))
    elif command.startswith("."):
        time.sleep(2)
    else:
        print("Invalid command")
    return("")

DR:我调用了两个函数。我希望它们的输出打印在同一行。

Answer 1

print()函数有额外的参数可以传递给它。你对end感兴趣。

def test1():
    print('hello ', end='')

def test2():
    print('there', end='')

test1()
test2()

>>> 
hello there
>>> 

不管它来自多少函数