我有一个多对多的领域,就像下面的模型一样:
class Project(models.Model):
name = models.CharField(verbose_name="Project Name", max_length=1000, blank = True, null = True)
number = models.IntegerField(verbose_name = "Project Number", blank =False ,null=False)
class Employee(models.Model):
name = models.CharField(verbose_name="Full Name", max_length=1000, blank = True, null = True)
number = models.IntegerField(verbose_name = "Number", blank = True ,null = True)
salary = models.IntegerField(verbose_name = "Salary", blank =True ,null=True)
departmentnum = models.IntegerField(verbose_name = "Department Number", blank = False ,null = False)
projects = models.ManyToManyField('Project')
我正在尝试获取每个员工从事的所有项目,并且卡在如何在我的观点中对此进行编码。我尝试过什么:
def employees(request):
if request.user.is_authenticated():
username = str(request.user.username)
employeeslist = Employee.objects.all().order_by('number')
projects = Employee.projects.all()
这显然是行不通的。任何帮助都会很棒!
只需按向后关系过滤employee
即可。 并且不要忘记distinct()
查询集:
projects = Project.objects.distinct().filter(employee__in=employeeslist)
如果要为每个员工输出项目,则无需将查询集传递给模板projects
:
{% for employee in employee_list %}
<h1>{{ employee.name }}</h1>
<ul>
{% for project in employee.projects.all %}
<li>{{ project.name }}</li>
{% endfor %}
</ul>
{% endfor %}
如果你想得到多对多的值,你可以写employeeslist.projects_set.all()
。