所以我的主要问题是这段代码的后半部分，特别是这个：
printf("Do you want to evaluate another teacher? (y/n) : ");
printf("n");
scanf(" %c", &loop);
if(loop != 'y' && loop != 3)
loop='n';
我正在创建一个接受调查的程序。但是，学生最多只能进行 3 次调查，并且在每次调查结束时都会询问他们是否要进行另一项调查。我的问题发生在他们进行第三次调查之后。之后，调查会提示相同的Do you want to evaluate another teacher? (y/n)问题，如果学生回答y代码会循环回来并让他们进行另一次调查，而不是听我的条件，在三次调查后，程序应该自动结束。如果他们回答n它仍然会重新进入循环！
对于如何使这部分代码与其余代码共存并正常工作，我感到非常困惑。帮助将不胜感激！
如果您愿意，这是我的全部代码：
#include <stdio.h>
int main()
{
int i = 0;
char loop='y';
while(loop == 'y' ){
for(i = 0; i<4; i++){
int num1,num2,num3,num4,num5,num6,num7,num8;
int result;
int input;
char name[30];
char teacher[30];
printf("Enter your name : ");
scanf("%s", &name);
printf("n");
printf("Which teacher do you want to evaluate : ");
scanf( "%s/n", &teacher);
printf("n");
printf("Answer with 1 for Never upto 7 for Frequentlyn");
printf("n");
printf("How often does the teacher indicate where the class is going? n ");
scanf("%d",&num1);
printf("How often does the teacher explain material clearly? n ");
scanf("%d",&num2);
printf("How often is the teacher available outside of class? n ");
scanf("%d",&num3);
printf("How often does the teacher provide helpful comments on papers and exams? n ");
scanf("%d",&num4);
printf("How often does the teacher stimulate interest in material? n ");
scanf("%d",&num5);
printf("How often does the teacher adjust the pace of class to the students' level of understanding? n ");
scanf("%d",&num6);
printf("How often does the teacher effectively encourage students to ask questions and give answers? n ");
scanf("%d",&num7);
printf("How is the teacher tolerant of different opinions expressed in class? n ");
scanf("%d",&num8);
printf("******************************************************************************n");
printf("******************************************************************************n");
printf("Student's name : %s.n", name);
printf("Teacher's name : %s.n", teacher);
printf("How often does the teacher indicate where the class is going: %dn",num1);
printf("How often does the teacher explain material clearly : %dn",num2);
printf("How often is the teacher available outside of class : %dn",num3);
printf("How often does the teacher provide helpful comments on papers and exams: %dn",num4);
printf("How often does the teacher stimulate interest in material: %dn",num5);
printf("How often does the teacher adjust the pace of class to the students' level of understanding: %dn",num6);
printf("How often does the teacher effectively encourage students to ask questions and give answers: %dn",num7);
printf("How is the teacher tolerant of different opinions expressed in class: %dn",num8);
printf("******************************************************************************n");
printf("******************************************************************************n");
printf("Do you want to evaluate another teacher? (y/n) : ");
printf("n");
scanf(" %c", &loop);
if(loop != 'y' && loop != 3)
loop='n';
}
return 0;
}
}
你真的需要while和for循环吗？for循环在做什么？
在你的代码中，你有两个循环，只要小心一点，你应该能够把它简化为其中一个。特别是，看起来您的return在while循环内，这意味着它是......很困惑。弄清楚你的循环应该做什么，然后再试一次。
if 语句
if(loop != 'y' && loop != 3)
loop='n';
应该在 for 循环之外。在任何情况下，您都不需要这两个循环。您应该将其更改为仅使用单个循环。而这个if语句应该是循环结束前的最后一个语句。
您无缘无故地使用了 2 个循环，而且您每次都询问用户名......
这是你应该怎么做：
#include <stdio.h>
int main()
{
int i = 0;
char loop;
int count=0; //new variable to know how many times he filled the survey
//You dont need to ask about your name everytime...
char name[30];
printf("Enter your name : ");
scanf("%s", &name);
printf("n");
do{
int num1,num2,num3,num4,num5,num6,num7,num8;
int result;
int input;
char teacher[30];
printf("Which teacher do you want to evaluate : ");
scanf( "%s/n", &teacher);
printf("n");
printf("Answer with 1 for Never upto 7 for Frequentlyn");
printf("n");
printf("How often does the teacher indicate where the class is going? n ");
scanf("%d",&num1);
printf("How often does the teacher explain material clearly? n ");
scanf("%d",&num2);
printf("How often is the teacher available outside of class? n ");
scanf("%d",&num3);
printf("How often does the teacher provide helpful comments on papers and exams? n ");
scanf("%d",&num4);
printf("How often does the teacher stimulate interest in material? n ");
scanf("%d",&num5);
printf("How often does the teacher adjust the pace of class to the students' level of understanding? n ");
scanf("%d",&num6);
printf("How often does the teacher effectively encourage students to ask questions and give answers? n ");
scanf("%d",&num7);
printf("How is the teacher tolerant of different opinions expressed in class? n ");
scanf("%d",&num8);
printf("******************************************************************************n");
printf("******************************************************************************n");
printf("Student's name : %s.n", name);
printf("Teacher's name : %s.n", teacher);
printf("How often does the teacher indicate where the class is going: %dn",num1);
printf("How often does the teacher explain material clearly : %dn",num2);
printf("How often is the teacher available outside of class : %dn",num3);
printf("How often does the teacher provide helpful comments on papers and exams: %dn",num4);
printf("How often does the teacher stimulate interest in material: %dn",num5);
printf("How often does the teacher adjust the pace of class to the students' level of understanding: %dn",num6);
printf("How often does the teacher effectively encourage students to ask questions and give answers: %dn",num7);
printf("How is the teacher tolerant of different opinions expressed in class: %dn",num8);
printf("******************************************************************************n");
printf("******************************************************************************n");
count++;
if (count<3) {
printf("Do you want to evaluate another teacher? (y/n) : ");
printf("n");
scanf("%s", &loop);
}
} while (loop=='y' && count<3);
return 0;
}
这是一个更正的版本。我只关注你问的问题，而不是你的代码可能存在的任何其他问题。
int main() {
int i;
char loop;
for(i = 0; i < 3; i++) {
if(i != 0) { //After the first survey, prompt before we interview them
printf("Do you want to evaluate another teacher? (y/n) : n");
scanf(" %c", &loop);
if(loop != 'y')
break; //Quit the loop
}
//*** Survey prompts here ***
}
}