哈希的迭代:杰基II

Question

嗨，我试图提取这个("波尔克县"，"short_name"=>"波尔克县"(在这个哈希的第 3 行，但我似乎只能得到"波尔克县"这是我当前的代码：

{% for county_hash in location.address_components %}
 {% for county in county_hash %}
  {{ county.long_name }}
 {% endfor %}
{% endfor %}
{
"0" => {
    "long_name" => "426", "short_name" => "426", "types" => ["street_number"]
}, "1" => {
    "long_name" => "Swanee Drive", "short_name" => "Swanee Dr", "types" => ["route"]
}, "2" => {
    "long_name" => "Livingston", "short_name" => "Livingston", "types" => ["locality", "political"]
}, "3" => {
    "long_name" => "Polk County", "short_name" => "Polk County", "types" => ["administrative_area_level_2", "political"]
}, "4" => {
    "long_name" => "Texas", "short_name" => "TX", "types" => ["administrative_area_level_1", "political"]
}, "5" => {
    "long_name" => "United States", "short_name" => "US", "types" => ["country", "political"]
}, "6" => {
    "long_name" => "77351", "short_name" => "77351", "types" => ["postal_code"]
}, "7" => {
    "long_name" => "8238", "short_name" => "8238", "types" => ["postal_code_suffix"]
}

}

Answer 1

虽然我不清楚你到底想在这里问什么，但以下代码

{% for county_hash in location.address_components %}
  {% for county in county_hash %}
    {{ county.long_name }}
  {% endfor %}
{% endfor %}

将return一串所有long_names，即您在评论中提到的426 Swanee Drive Livingston Polk County Texas United States 77351 8238。

---

如果你只需要Polk County，你必须使用where过滤器：

{% for county_hash in location.address_components %}
  {% for county in county_hash %}
    {{ county.long_name | where: "shortname", "Polk County" }}
  {% endfor %}
{% endfor %}

Answer 2

感谢您的帮助，这种方法对我有用。

{% for county_hash in location.address_components %}
  {% for county in county_hash %}
    {% if county.long_name contains 'County' %}
     {{ county.long_name }}
    {% endif %}
  {% endfor %}
{% endfor %}

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