Javascript / Blockchain.info Websocket API Address Subscript

Question

我是比特币的新手，Blockchain.info API和javascript，但是，我正在尝试实现一个代码来跟踪特定比特币地址上的实时支付通知。这里的想法是...用户扫描<img src="http://chart.googleapis.com/chart?chs=200x200&cht=qr&chl=12fMma2J15qre9bZPsX3AerdgWd9Poe9ee">二维码图像，并向BTC地址付款后，12fMma2J15qre9bZPsX3AerdgWd9Poe9ee，ID #websocket的Div将立即显示实时(不刷新网页(，转移到该地址的比特币数量，从而将div的初始内容从monitoring...切换到Recieved: 0.003 BTC转移的金额。

我写了一段代码...但我不确定我错过了什么。请帮忙。谢谢。

代码：

        <div class="row">
            <div class="col-md-4 "> 
                <img src="http://chart.googleapis.com/chart?chs=200x200&cht=qr&chl=12fMma2J15qre9bZPsX3AerdgWd9Poe9ee"> 
                <div id="websocket">
                    Monitoring Transactions ...
                </div>
                <script>
                var btcs = new WebSocket("12fMma2J15qre9bZPsX3AerdgWd9Poe9ee");
                btcs.onopen = function() {
                    btcs.send(JSON.stringify({"op":"addr_sub", "addr":"12fMma2J15qre9bZPsX3AerdgWd9Poe9ee"}));
                };
                btcs.onmessage = function (onmsg) {
                    var response = JSON.parse(onmsg.data);
                    var getOutputs = response.x.out;
                    var countOuts = getOutputs.length;
                    for (i=0; i < countOuts; i++){
                        var outAdd = response.x.out[i].addr;
                        var address = "12fMma2J15qre9bZPsX3AerdgWd9Poe9ee";
                        if (outAdd == address){
                            var amount =response.x.out[i].value;
                            var calAmount = Amount / 100000000;
                            document.getElementById("websocket").innerHTML = "Recieved" + calAmount + "BTC";
                        }
                    }
                };
                </script>
            </div>
            <div class="col-md-8">
                <!-- more html stuff goes here -->
            </div>
        </div>

Answer 1

我在

代码中没有看到与区块链 API 的连接，所以我猜这个

var btcs = new WebSocket("12fMma2J15qre9bZPsX3AerdgWd9Poe9ee");

应该使用 API 的地址而不是目标比特币钱包地址。

Answer 2

可能需要在

地址位置启动新套接字时放置wss://ws.blockchain.info/inv。

Answer 3

    <div class="row">
        <div class="col-md-4 "> 
            <img src="http://chart.googleapis.com/chart?chs=200x200&cht=qr&chl=12fMma2J15qre9bZPsX3AerdgWd9Poe9ee"> 
            <div id="websocket">
                Monitoring Transactions ...
            </div>
            <script>
            var btcs = new WebSocket("wss://ws.blockchain.info/inv");
            btcs.onopen = function() {
                btcs.send(JSON.stringify({"op":"addr_sub", "addr":"12fMma2J15qre9bZPsX3AerdgWd9Poe9ee"}));
            };
            btcs.onmessage = function (onmsg) {
                var response = JSON.parse(onmsg.data);
                var getOutputs = response.x.out;
                var countOuts = getOutputs.length;
                for (i=0; i < countOuts; i++){
                    var outAdd = response.x.out[i].addr;
                    var address = "12fMma2J15qre9bZPsX3AerdgWd9Poe9ee";
                    if (outAdd == address){
                        var amount =response.x.out[i].value;
                        var calAmount = Amount / 100000000;
                        document.getElementById("websocket").innerHTML = "Recieved" + calAmount + "BTC";
                    }
                }
            };
            </script>
        </div>
        <div class="col-md-8">
            <!-- more html stuff goes here -->
        </div>
    </div>