基于Actionscript 2.0(adobeflash cs6)的平铺移动

Question

所以我遇到了这个问题，我不知道如何为动作脚本2.0编写可能的基于瓦片的4个方向移动(NSWE(代码。

我有这个代码，但它是动态移动的，它使字符在所有8个方向上移动(NW、NE、SW、SE N、S、W、E(。目标是将移动限制在基于瓦片的且仅在4个方向上(NSEW(

onClipEvent(enterFrame)
{
speed=5;
if(Key.isDown(Key.RIGHT))
{
this.gotoAndStop(4);
this._x+=speed;
}
if(Key.isDown(Key.LEFT))
{
this.gotoAndStop(3);
this._x-=speed;
}
if(Key.isDown(Key.UP))
{
this.gotoAndStop(1);
this._y-=speed;
}
if(Key.isDown(Key.DOWN))
{
this.gotoAndStop(2);
this._y+=speed;
}
}

Answer 1

最简单直接的方法是沿着X-轴或沿着Y-轴移动，一次只移动一个，而不是同时移动两个。

onClipEvent(enterFrame)
{
speed = 5;
dx = 0;
dy = 0;
// Figure out the complete picture of keyboard input.
if (Key.isDown(Key.RIGHT))
{
dx += speed;
}
if (Key.isDown(Key.LEFT))
{
dx -= speed;
}
if (Key.isDown(Key.UP))
{
dy -= speed;
}
if (Key.isDown(Key.DOWN))
{
dy += speed;
}
if (dx != 0)
{
// Move along X-axis if LEFT or RIGHT pressed.
// Ignore if it is none or both of them.
this._x += dx;
if (dx > 0)
{
this.gotoAndStop(4);
}
else
{
this.gotoAndStop(3);
}
}
else if (dy != 0)
{
// Ignore if X-axis motion is already applied.
// Move along Y-axis if UP or DOWN pressed.
// Ignore if it is none or both of them.
this._y += dy;
if (dy > 0)
{
this.gotoAndStop(2);
}
else
{
this.gotoAndStop(1);
}
}
}