我一直在努力研究如何让一个经过检查的绑定与Knockout和JQuery Mobile一起工作。由于某些原因,香草Knockout JS"检查"绑定不起作用:
<fieldset data-role="controlgroup">
<legend>Your favorite flavor:legend>
<input type="radio" name="flavor-selection" value="Chocolate" id="flavor-selection-chocolate" data-bind="checked: flavor" />
<label for="flavor-selection-chocolate">Normal</label>
<input type="radio" name="flavor-selection" value="Vanilla" id="flavor-selection-vanilla" data-bind="checked: flavor" />
<label for="flavor-selection-vanilla">Party</label>
</fieldset>
有什么想法吗?
事实证明,jQuery Mobile为单选按钮设置标签样式,以便显示单选选择(隐藏实际的单选按钮本身)。
我尝试了一下这里的建议:http://codeclimber.net.nz/archive/2013/08/16/How-to-bind-a-jquery-mobile-radio-button-list-to.aspx但没有取得任何成功——我怀疑它可能只适用于jQueryMobile的前一个版本。
这是我的选择:
根据隐藏复选框的选中状态,创建一个自定义绑定来切换标签上的"ui radio on"one_answers"ui radio-off"类:
ko.bindingHandlers.jqMobileRadioChecked = {
init: function (element, valueAccessor, allBindingsAccessor, data, context) {
ko.bindingHandlers.checked.init(element, valueAccessor, allBindingsAccessor, data, context);
},
update: function (element, valueAccessor, allBindingsAccessor, data, context) {
var viewModelValue = valueAccessor();
var viewModelValueUnwrapped = ko.unwrap(viewModelValue);
var $el = $(element);
var $label = $el.siblings("label[for='" + $el.attr("id") + "']");
if (viewModelValueUnwrapped === $el.val()) {
$label.removeClass("ui-radio-off");
$label.addClass("ui-radio-on");
} else {
$label.removeClass("ui-radio-on");
$label.addClass("ui-radio-off");
}
}
};
然后HTML就变成了:
<fieldset data-role="controlgroup">
<legend>Your favorite flavor:legend>
<input type="radio" name="flavor-selection" value="Chocolate" id="flavor-selection-chocolate" data-bind="jqMobileRadioChecked: flavor" />
<label for="flavor-selection-chocolate">Normal</label>
<input type="radio" name="flavor-selection" value="Vanilla" id="flavor-selection-vanilla" data-bind="jqMobileRadioChecked: flavor" />
<label for="flavor-selection-vanilla">Party</label>
</fieldset>