在调用.apply()之后,如何保留我原始功能的此上下文



i具有一个函数,该功能接受函数作为参数。我想操纵该函数在功能A中的参数,并将其返回为functionc。我发现我可以使用.apply()来执行此操作,但是函数的原始上下文丢失了,而是由功能A替换。

例如,

var factory = {
   return {
       fnB: function() {}  
   }
};
fnA(fn) {
    return fnC(params) {
        var customparams = [params, {something: else}]
        return method.apply(null, customparams);
     }
}
var load = fnA(factory.fnB);
load(params);

但是,当我执行加载(参数)时,我会丢失functionb的上下文。函数b定义为工厂的方法。我该怎么做?谢谢!

我将假设method实际上是fn,并且functionB是分配给对象属性的函数,并且您的实际代码中不存在各种语法错误:

var obj = {
    name: "foo",
    functionB: function() {
        console.log(this.name); // <== Using `this` to refer to `obj`
    }
};
function functionA(fn) {
    return function functionC(params) {
        var customparams = [params, {something: "else"}];
        return fn.apply(null, customparams);
    };
}
var load = functionA(obj.functionB);
load("a", "b"); // Fails because `this` in the call to `functionB` isn't `obj`

如果是这样,您可以在几个wasy中修复它:

1)使用 Function#bind whne将 functionB传递到 functionA

var load = functionA(obj.functionB.bind(obj));
load("a", "b"); // Works

var obj = {
  name: "foo",
  functionB: function() {
    snippet.log(this.name); // <== Using `this` to refer to `obj`
  }
};
function functionA(fn) {
  return function functionC(params) {
    var customparams = [params, {
      something: "else"
    }];
    return fn.apply(null, customparams);
  };
}
var load = functionA(obj.functionB.bind(obj));
load("a", "b"); // Works
<!-- Script provides the `snippet` object, see http://meta.stackexchange.com/a/242144/134069 -->
<script src="http://tjcrowder.github.io/simple-snippets-console/snippet.js"></script>

2)正如Bergi所建议的那样,通过向functionA添加第二个参数,它在调用fn时使用(请参见摘要中)&nbsp;&mdash;例如,许多ES5 Array方法都使用了这种方法:

var obj = {
  name: "foo",
  functionB: function() {
    snippet.log(this.name);
  }
};
function functionA(fn, thisArg) {           // <=== Accepting thisArg
  return function functionC(params) {
    var customparams = [params, {
      something: "else"
    }];
    return fn.apply(thisArg, customparams); // <=== Using it
  };
}
var load = functionA(obj.functionB, obj);   // <=== Passing it
load("a", "b"); // Works
<!-- Script provides the `snippet` object, see http://meta.stackexchange.com/a/242144/134069 -->
<script src="http://tjcrowder.github.io/simple-snippets-console/snippet.js"></script>

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