Google Maps API-使用PHP检索城市和州

Question

我目前正在使用Google Maps API来获得经度和纬度，形成了用户的街道，街道号码和邮政编码。

我也想从地图API结果中抓住他们的城市并说明。XML文档格式却很奇怪，我不确定我应该如何引用它（这与我抓住长长和lat的方式不同）。

这就是我加载地图API的方式：

$map_address = str_replace($address."+".$zip);
$map_api_url = "https://maps.googleapis.com/maps/api/geocode/json?address=".$map_address."&key=myKey";
$resp_json = file_get_contents($map_api_url);
$resp = json_decode($resp_json, true);

我得到了长长的时间：

$lati = $resp['results'][0]['geometry']['location']['lat'];
$longi = $resp['results'][0]['geometry']['location']['lng'];

但是我该如何抓住城市和州？

{
   "results" : [
  {
     "address_components" : [
        {
           "long_name" : "3840",
           "short_name" : "3840",
           "types" : [ "street_number" ]
        },
        {
           "long_name" : "Fake Street",
           "short_name" : "Fake St",
           "types" : [ "route" ]
        },
        {
           "long_name" : "Wilson Heights",
           "short_name" : "Wilson Heights",
           "types" : [ "neighborhood", "political" ]
        },
        {
           "long_name" : "North York",
           "short_name" : "North York",
           "types" : [ "sublocality_level_1", "sublocality", "political" ]
        },
        {
           "long_name" : "Toronto",
           "short_name" : "Toronto",
           "types" : [ "locality", "political" ]
        },
        {
           "long_name" : "Toronto Division",
           "short_name" : "Toronto Division",
           "types" : [ "administrative_area_level_2", "political" ]
        },
        {
           "long_name" : "Ontario",
           "short_name" : "ON",
           "types" : [ "administrative_area_level_1", "political" ]
        },
        {
           "long_name" : "Canada",
           "short_name" : "CA",
           "types" : [ "country", "political" ]
        },
        {
           "long_name" : "M6H",
           "short_name" : "M6H",
           "types" : [ "postal_code_prefix", "postal_code" ]
        }
     ],
     "formatted_address" : "3840 Fake Street, Toronto, ON M6H, Canada",
     "geometry" : {
        "location" : {
           "lat" : 43.5399244,
           "lng" : -78.43486559999999
        },
        "location_type" : "ROOFTOP",
        "viewport" : {
           "northeast" : {
              "lat" : 43.5412733802915,
              "lng" : -78.43351661970848
           },
           "southwest" : {
              "lat" : 43.7385754197085,
              "lng" : -79.43621458029151
           }
        }
     },
     "place_id" : "ChIJPVDxjGgyK4gRt3O7zOSmIF4",
     "types" : [ "street_address" ]
  }
],
"status" : "OK"
}

Answer 1

刚刚通过循环运行代码来回答我自己的问题。请让我知道您是否有更好的方法！

foreach($resp['results'][0]['address_components'] as $address_componenets) {
    if($address_componenets["types"][0]=="country") {
        $country = $address_componenets["long_name"];
    }
    if($address_componenets["types"][0]=="administrative_area_level_1") {
        $state = $address_componenets["long_name"];
    }   
    if($address_componenets["types"][0]=="locality") {
        $city = $address_componenets["long_name"];
    }   
}