Laravel查询以sub阵列没有雄辩的结果

Question

请在学校的项目中帮助我。我如何在Laravel控制器中查询这种情况。我有三张桌子：shipping_table和shipping_products and tbl_products，现在我的桌子结构是：

运输表：

Ship_ID (INT AUTO INC)
AMOUNT (DOUBLE,2)
NAME (VARCHAR)
SHIP_DATE (DATE)
RECEIVER (VARCHAR)

shipping_products：

ID (INT AUTO INC)
Ship_id (foreign key from shipping table)
Product_id

products_table：

Product_id (Auto Inc)
name(varchar)
Qty(int)
Description (varchar)

现在我想要的是这样的查询结果：我想把所有的东西都放在运输桌上，在子阵列中，我想获得带有所需运输ID的Shippting_products中列出的产品。

类似的结果：示例我有2个shipping_table值

Array(2) {
 [0] Array(4) {
  ['Ship_id'] "1"
  ['Amount'] "10000"
  ['Ship_date'] "1995-12-11"
  ['Ship_products'] Array(3)
      ['id'] "1" Array(2)
           ['product_id'] "5"
           ['name'] "Product 1"
      ['id'] "2" Array(2)
           ['product_id'] "6"
           ['name'] "Product 2"
      ['id'] "3" Array(2)
           ['product_id'] "10"
           ['name'] "Product 15"
 }
 [1] Array(4) {
   ['Ship_id'] "2"
   ['Amount'] "15000"
   ['Ship_date'] "1995-12-15"
   ['Ship_products'] Array(2)
      ['id'] "1" Array(2)
           ['product_id'] "5"
           ['name'] "Product 1"
      ['id'] "2" Array(2)
           ['product_id'] "6"
           ['name'] "Product 2"
 }
}

Answer 1

SQL零件很容易（使用JOINS）

SELECT * 
FROM Shipping S
LEFT JOIN Shipping_Products SP
  ON SP.Ship_Id=S.Ship_Id
LEFT JOIN Products P
  ON P.Product_id=SP.Product_id

php零件更为复杂，因为您必须以循环获取结果并检测Ship_id和Product_id的更改并放入生成的数组中。

因为这是作业..我将其作为练习...

---

这是一个快速算法示例 - 未经测试但合理的声音。

$cur_ship = '';
$cur_prod = '';
$results  = array();
foreach ($resultset as $key => $row) {
   if ($cur_ship != $row['Ship_id']) {
      $cur_ship = $row['Ship_id'];
      $cur_prod = '';
      $results[$cur_ship] = array();
      // Fill ship info from $row
   }
   if ($cur_prod != $row['Product_id']) {
      $cur_prod = $row['Product_id'];
      $results[$cur_ship][$cur_prod] = array();
      // Fill Product info from $row
   }
   // FILL OUR $results[$cur_ship][$cur_prod] from $row
}