Spring MVC调度程序不工作.HTTP 404

Question

我见过很多类似的线程，但没有解决我的'问题?'。请告诉我我错过了什么?当我尝试去http://localhost:8080/helloworld.html我得到"HTTP状态404"。

HelloWorldController.java

   @Controller
    public class HelloWorldController {
   @RequestMapping(value="/helloworld.html")
    public ModelAndView helloWorld() {
        return new ModelAndView("HelloWorldPage"); }
     } 

web . xml

    <?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee
         http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"
         version="3.1">
    <servlet>
        <servlet-name>dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>dispatcher</servlet-name>
        <url-pattern>*.html</url-pattern>
    </servlet-mapping>
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/dispatcher-servlet.xml</param-value>
    </context-param>
</web-app>

dispatcher-servlet.xml

   <beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:context="http://www.springframework.org/schema/context"
       xsi:schemaLocation="
       http://www.springframework.org/schema/beans
       http://www.springframework.org/schema/beans/spring-beans.xsd
       http://www.springframework.org/schema/context
       http://www.springframework.org/schema/context/spring-context.xsd">
    <context:component-scan base-package="com.site.controller"/>
    <bean
    class="org.springframework.web.servlet.view.InternalResourceViewResolver">
     <property name="prefix" value="/WEB-INF/pages/" />
     <property name="suffix" value=".jsp"/>
    </bean>
    </beans>

文件结构:https://s18.postimg.org/4j699vn6x/stack.png

pom.xml

...
    <dependencies>
        <dependency>
        <groupId>org.springframework</groupId>
        <artifactId>spring-context</artifactId>
        <version>3.1.0.RELEASE</version>
        </dependency>
        <dependency>
        <groupId>org.springframework</groupId>
        <artifactId>spring-webmvc</artifactId>
        <version>3.1.0.RELEASE</version>
        </dependency>
    </dependencies>
...

Answer 1

你应该这样配置你的应用程序:

在你的web.xml中，你应该像这样配置dispatcher servlet:

<servlet>
    <servlet-name>dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/dispatcher-servlet.xml</param-value>
        </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
    <servlet-name>dispatcher</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

控制器应该是这样的:

@Controller
public class HelloWorldController {
   @RequestMapping(value="/")
   public ModelAndView helloWorld() {
        return new ModelAndView("HelloWorldPage"); }
   }

现在，根据你的图像，我猜你的tomcat上下文是untitled7，所以tomcat启动后&尝试点击下一个URL:

http://localhost: 8080/untitled7