My Rectangle.h
namespace shapes {
class Rectangle {
public:
int x0, y0, x1, y1;
Rectangle();
Rectangle(int x0, int y0, int x1, int y1);
~Rectangle();
int getArea();
};
}
我Rectangle.cpp #include "Rectangle.h"
namespace shapes {
Rectangle::Rectangle() { }
Rectangle::Rectangle(int X0, int Y0, int X1, int Y1) {
x0 = X0;
y0 = Y0;
x1 = X1;
y1 = Y1;
}
Rectangle::~Rectangle() { }
int Rectangle::getArea() {
return (x1 - x0) * (y1 - y0);
}
}
我rect.pyx # distutils: language = c++
# distutils: sources = Rectangle.cpp
cdef extern from "Rectangle.h" namespace "shapes":
cdef cppclass Rectangle:
Rectangle() except +
Rectangle(int, int, int, int) except +
int x0, y0, x1, y1
int getArea()
cdef class PyRectangle:
cdef Rectangle c_rect
def __cinit__(self, int x0, int y0, int x1, int y1):
self.c_rect = Rectangle(x0, y0, x1, y1)
def get_area(self):
return self.c_rect.getArea()
cdef public int cythonfunc(PyRectangle py_rect):
result = py_rect.get_area()
return result
我main.cpp #include <Python.h>
#include "rect.h"
#include "Rectangle.h"
#include <iostream>
int main (int argc, char *argv[])
{
int result;
Py_Initialize();
PyInit_rect();
shapes::Rectangle c_rect = shapes::Rectangle(0,0,2,1);
result = cythonfunc(c_rect);
std::cout<<result<<"n";
Py_Finalize();
return 0;
}
我的Makefile all:
cython3 --cplus rect.pyx
c++ -g -O2 -c rect.cpp -o rect.o `python3-config --includes`
c++ -g -O2 -c Rectangle.cpp -o Rectangle.o `python3-config --includes`
c++ -g -O2 -c main.cpp -o main.o `python3-config --includes`
c++ -g -O2 -o rect Rectangle.o rect.o main.o `python3-config --libs`
clean:
rm -f rect rect.cpp rect.h *.o
我的问题与rect.pyx中的"cythonfunc"有关。这是一个公共函数,可以用一个矩形结构体/对象作为参数从main调用,并返回一个区域给main.cpp。
我试过c结构和python对象,两者都不适合我。如果我使用这些代码,编译器会给出
的错误。Error compiling Cython file:
------------------------------------------------------------
...
def __cinit__(self, int x0, int y0, int x1, int y1):
self.c_rect = Rectangle(x0, y0, x1, y1)
def get_area(self):
return self.c_rect.getArea()
cdef public int cythonfunc(PyRectangle py_rect):
^
------------------------------------------------------------
rect.pyx:19:27: Function declared public or api may not have private types
所以我添加了"public"到PyRectangle,但是得到了另一个错误:
Error compiling Cython file:
------------------------------------------------------------
...
Rectangle() except +
Rectangle(int, int, int, int) except +
int x0, y0, x1, y1
int getArea()
cdef public class PyRectangle:
^
------------------------------------------------------------
rect.pyx:12:5: Type object name specification required for 'public' C class
如果我把cythonfunction改成:
cdef public int cythonfunc(Rectangle c_rect):
result = c_rect.getArea()
return result
I got error of:
In file included from main.cpp:3:0:
rect.h:21:42: warning: ‘cythonfunc’ initialized and declared ‘extern’
__PYX_EXTERN_C DL_IMPORT(int) cythonfunc(shapes::Rectangle);
^
rect.h:21:42: error: ‘shapes’ has not been declared
main.cpp: In function ‘int main(int, char**)’:
main.cpp:17:29: error: ‘cythonfunc’ cannot be used as a function
result = cythonfunc(c_rect);
^
我只能成功地将单独的x0, y0, x1, y1作为参数传递给cythonfunction。是否有一种正确的方法来传递cpp结构/对象或python对象作为参数到cython公共函数?
关于您的第二次尝试(这可能是从c++调用它的更明智的方式,尽管我将通过引用传递):
cdef public int cythonfunc(Rectangle c_rect):
result = c_rect.getArea()
return result
问题是它不知道Rectangle
是什么,因为Cython生成的rect.h
不包括Rectangle.h
。修复此问题的最简单方法是交换main.cpp
中包含的顺序:
#include "Rectangle.h" // this one is now first
#include "rect.h"
错误"shapes has not been declarations "告诉你这个…
尊重你的第一次尝试,你是正确的,你必须让PyRectangle
公开。为此,您还需要像Cython告诉您的那样指定一个"类型对象名称"。您可以这样做(尽管实际上不是很清楚…):
cdef public class PyRectangle [object c_PyRect, type c_PyRect_t]:
# ... as before
这确保了PyRectangle作为struct c_PyRect
对C/c++可用(因此cythonfunc
签名是int cythonfunc(struct c_PyRect *);
)
同样,定义PyRectangle
的Python TypeObject
可以作为c_PyRect_t
使用,但您不需要它。