无法使用 OAuth 初学者工具包进行共享LinkedIn

Question

我使用 OAuthStarter Kit 访问 LinkedIn API。我成功获得了权限的访问令牌。

rw_ns r_basicprofile r_fullprofile

可以获取个人资料详细信息以及仅共享评论，并在共享URL或图像或描述等时...我使用以下代码：

-(void)postUpdate
 {
   NSURL *url = [NSURL URLWithString:@"http://api.linkedin.com/v1/people/~/shares"];
   OAMutableURLRequest *request =
   [[OAMutableURLRequest alloc] initWithURL:url
                            consumer:[self getConsumer]
                               token:self.accesstoken
                            callback:nil
                   signatureProvider:nil];
   NSDictionary *update = [[NSDictionary alloc] initWithObjectsAndKeys:
                    
                    [[NSDictionary alloc]
                     initWithObjectsAndKeys:
                     @"anyone",@"code",nil], @"visibility",
                    @"title goes here",@"title",
                    @"comment goes here", @"comment",
                    @"description goes here",@"description",
                     @"www.google.com",@"submitted-url",
                    @"http://economy.blog.ocregister.com/files/2009/01/linkedin-logo.jpg",@"submitted-image-url",
                    nil];
   [request setValue:@"json" forHTTPHeaderField:@"x-li-format"];
   [request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
   NSString *updateString = [update JSONString];
   [request setHTTPBodyWithString:updateString];
    [request setHTTPMethod:@"POST"];
   OADataFetcher *fetcher = [[OADataFetcher alloc] init];
   [fetcher fetchDataWithRequest:request
                 delegate:self
        didFinishSelector:@selector(postUpdateApiCallResult:didFinish:)
          didFailSelector:@selector(postUpdateApiCallResult:didFail:)];
  }

但是我收到如下响应错误：

 2012-10-09 18:27:29.906 SocialConnectTest[9460:19a03] data {
 "errorCode": 0,
 "message": "Invalid xml {Expected elements 'post-network-update@http://api.linkedin.com/v1 id@http://api.linkedin.com/v1 visibility@http://api.linkedin.com/v1 comment@http://api.linkedin.com/v1 attribution@http://api.linkedin.com/v1 content@http://api.linkedin.com/v1 private-message@http://api.linkedin.com/v1 share-target-reach@http://api.linkedin.com/v1' instead of 'submitted-url@http://api.linkedin.com/v1' here in element share@http://api.linkedin.com/v1}",
 "requestId": "W2G7WJDHOJ",
 "status": 400,
 "timestamp": 1349787449685
}

我不知道问题出在哪里。我该如何解决这个问题？

Answer 1

我修复了它。问题出在帖子参数上

1. 根据 API 中链接的文档，如果我们在请求正文中使用 JSON然后，后参数的键必须采用驼峰大小写，而在 XML 中，使用分隔的键名"-"。
共享参数，如提交网址，
2. 子提交图像网址，描述，标题等必须是称为**内容的键的值。

所以我修改了代码如下。.

-(void)postUpdateHERE
{
  NSURL *url = [NSURL URLWithString:@"http://api.linkedin.com/v1/people/~/shares"];
  OAMutableURLRequest *request =
  [[OAMutableURLRequest alloc] initWithURL:url
                            consumer:[self getConsumer]
                               token:self.accesstoken
                            callback:nil
                   signatureProvider:nil];
  NSDictionary *update = [[NSDictionary alloc] initWithObjectsAndKeys:
                    [[NSDictionary alloc]
                     initWithObjectsAndKeys:
                     @"anyone",@"code",nil], @"visibility",
                    @"comment goes here", @"comment",
                    [[NSDictionary alloc]
                     initWithObjectsAndKeys:
                    @"description goes here",@"description",
                    @"www.google.com",@"submittedUrl",
                      @"title goes here",@"title",
                    @"http://economy.blog.ocregister.com/files/2009/01/linkedin-logo.jpg",@"submittedImageUrl",nil],@"content",
                    nil];
  [request setValue:@"json" forHTTPHeaderField:@"x-li-format"];
  [request setValue:@"application/xml" forHTTPHeaderField:@"Content-Type"];
  NSString *updateString = [update JSONString];
  [request setHTTPBodyWithString:updateString];
  [request setHTTPMethod:@"POST"];
  OADataFetcher *fetcher = [[OADataFetcher alloc] init];
  [fetcher fetchDataWithRequest:request
                 delegate:self
        didFinishSelector:@selector(postUpdateApiCallResult:didFinish:)
          didFailSelector:@selector(postUpdateApiCallResult:didFail:)];
}

现在代码对我有用..