如何将系列分成两列熊猫

Question

我有三个充满数据的列表，我想将它们连接起来以创建一个数据帧

type of data_activationsLV : list
type of data_activationsF : list
type of data_activationsPC : list

三个列表的数据结构：

data_activationsLV     data_activationsF       data_activationsPC
    index    a         index     b              index     c
    14468    7.8       14468     7.2            14468     7.6         
    14469    7.8       14469     7.1            14469     7.0
    14470    7.9       14470     7.9            14470     8.1
    14471    8.2       14471     9.5            14471     9.9

..

我将它们转换为系列并确认它们：

df15LV = pd.Series(data_activationsLV)
df15F = pd.Series(data_activationsF)
df15PC = pd.Series(data_activationsPC)
dfnew2=pd.concat([df15LV,df15F,df15PC], ignore_index=True, axis=1)

通过缺点，我在这里有一个问题，在每一列中，它都考虑旧列的名称及其带有值的索引

index    0              1                2
0        a14468  7.8    b14468   7.2     c14468   7.6
1        a14469  7.8    b14469   7.1     c14469   7.0
2        a14470  7.9    b14470   7.9     c14470   8.1
3        a14471  8.2    b14471   9.5     c14471   9.9

所以我测试了拆分函数：

dfnew2['a'] = dfnew2[2].split(' ')

但是它不起作用，当我尝试拆分这些列时，就会发生这种情况：

AttributeError: 'Series' object has no attribute 'split'

是否可以只包含每列的值：

index    df15LV     df15F      df15PC
0        7.8        7.2        7.6
1        7.8        7.1        7.0
2        7.9        7.9        8.1
3        8.2        9.5        9.9

Answer 1

我认为您需要使用 str.split 拆分apply并使用str[1]进行选择：

print (data_activationsLV)
['14468  7.8', '14469  7.8']
print (data_activationsF)
['14468  7.2', '14469  7.1', '14470  7.9', '14471  9.5']
print (data_activationsPC)
['14468  7.6', '14470  8.1', '14471  9.9']
df15LV = pd.Series(data_activationsLV)
df15F = pd.Series(data_activationsF)
df15PC = pd.Series(data_activationsPC)
dfnew2=pd.concat([df15LV,df15F,df15PC], axis=1)
dfnew2 = dfnew2.apply(lambda x: x.str.split().str[1])
#if necessary convert to float
dfnew2 = dfnew2.astype(float)
print (dfnew2)
     0    1    2
0  7.8  7.2  7.6
1  7.8  7.1  8.1
2  NaN  7.9  9.9
3  NaN  9.5  NaN

另一种解决方案是使用 list comprehension 进行拆分：

print (data_activationsLV)
['7.8', '7.8']
print (data_activationsF)
['7.2', '7.1', '7.9', '9.5']
print (data_activationsPC)
['7.6', '8.1', '9.9']
df15LV = pd.Series(data_activationsLV)
df15F = pd.Series(data_activationsF)
df15PC = pd.Series(data_activationsPC)
dfnew2=pd.concat([df15LV,df15F,df15PC], axis=1)
#if necessary convert to float
dfnew2 = dfnew2.astype(float)
print (dfnew2)
     0    1    2
0  7.8  7.2  7.6
1  7.8  7.1  8.1
2  NaN  7.9  9.9
3  NaN  9.5  NaN

Answer 2

如果您有相同长度的列表，则可以创建一个空的数据帧并填充它：

data_activationsLV = [7.8,7.8,7.9,8.2]
data_activationsF = [7.2,7.1,7.9,9.5]
# create an empty dataframe
columns = ['LV', 'F']
index = np.arange(len(data_activationsLV)) # array of numbers for the number of rows
df = pd.DataFrame(columns=columns, index = index)
df['LV'] = data_activationsLV
df['F'] = data_activationsF
df