使用 JavaScript Reg 为 Angular5 应用程序验证英国邮政编码

Question

>我正在研究 Angular 5 反应式表单验证并尝试使用自定义验证功能验证英国邮政编码，该功能正在工作和测试，以防在邮政编码末尾提供额外的字母或数值第二部分，它验证 true，例如 NW10 5NW 是正确的，但如果我键入类似 NW10 5NWRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR

我尝试在 https://regexr.com/上遵循常规测试，它返回正确的响应，不确定为什么在 javaScript 中行为方式不同???

function postCodeValidator(control: FormControl)
{
let givenPostCode = control.value;
let UKPostCodePattern = /^([Gg][Ii][Rr] 0[Aa]{2})|((([A-Za-z][0-9]{1,2})|(([A-Za-z][A-Ha-hJ-Yj-y][0-9]{1,2})|(([A-Za-z][0-9][A-Za-z])|([A-Za-z][A-Ha-hJ-Yj-y][0-9]?[A-Za-z]))))s?[0-9][A-Za-z]{2})/;
var isUKPostCodeValid = UKPostCodePattern.test(givenPostCode); 
console.log("postcode validity ",isUKPostCodeValid,  " for ", givenPostCode);
if(!isUKPostCodeValid)
{
return {
postCode:{
required:"UK Valid PostCode",
provided: givenPostCode
}
}
}
return null;
}

Answer 1

尝试使用以下正则表达式

^(([Gg][Ii][Rr] 0[Aa]{2})|((([A-Za-z][0-9]{1,2})|(([A-Za-z][A-Ha-hJ-Yj-y][0-9]{1,2})|(([A-Za-z][0-9][A-Za-z])|([A-Za-z][A-Ha-hJ-Yj-y][0-9]?[A-Za-z]))))s?[0-9][A-Za-z]{2}))$

https://regexr.com/3pp3r