使用 LET 从 itab 填充范围表

Question

我找到了这个用于填充范围表的代码(源代码已经离线(：

DATA   lr_vkorg   TYPE RANGE OF vkorg.
TYPES: lr_range_t TYPE RANGE OF vkorg.
lr_vkorg = VALUE lr_range_t(
LET s = 'I'
o = 'EQ'
IN sign   = s
option = o
( low = '1100' )
( low = '1200' )
( low = '1300' )
( low = '1400' )
( low = '1500' )
).

但与其做这样的事情：

( low = '1' )
( low = '2' )
...

我想用内部表的值填充它['1', '2', ...].
有人知道如何做到这一点吗？

更新：这是我根据答案这样做的：

DATA:
lt_itab       TYPE TABLE OF string,
lt_range_itab TYPE RANGE OF string
.
APPEND '1'  TO lt_itab.
APPEND '2'  TO lt_itab.
APPEND '3'  TO lt_itab.
APPEND '4'  TO lt_itab.
lt_range_itab = VALUE #(
FOR <ls_itab> IN lt_itab
( sign = 'I'
option = 'EQ'
low = <ls_itab> )
).

Answer 1

您可以使用声明的结构声明宏，如下所示：

DEFINE range.
lr_vkorg = VALUE lr_range_t( BASE lr_vkorg ( sign = 'I' option = 'EQ' low = &1 ) ).
END-OF-DEFINITION.

然后用这句单行词填充您的范围：

range: '1100', '1200', '1300', '1400', '1500', '1600'.

如果我们谈论 itab 的填充范围，请使用以下语句：

lr_vkorg = VALUE #( FOR ls_vkorg IN gt_vkorg
( sign = 'I'
option = 'EQ'
low = ls_vkorg-vkorg )
).

Answer 2

lr_vkorg = VALUE # ( sign   = 'I'  option = 'EQ' ( low = '1100' ) ( low = '1200' )
( low = '1300' ) ( low = '1400' )   ( low = '1500' ) ).