如何排序数组列表哈希图在Android

Question

我从网站获取数据，并将该数据值纳入hashmap。我还创建了动态线性布局，并在其中显示ol hashmap值。现在问题来了，当我想按名称和数据类型显示哈希图值时，我该怎么做呢?

for (int i = 0; i < nodes.getLength(); i++)

{

        Element e = (Element) nodes.item(i);
        Node node = nodes.item(i);
        HashMap<String, String> map = new HashMap<String, String>();
        lin = new LinearLayout(this);
        lin.setOrientation(LinearLayout.VERTICAL);
        lin.setBackgroundResource(R.drawable.my_border);
        LinearLayout linbsc = new LinearLayout(this);
        linbsc.setOrientation(LinearLayout.HORIZONTAL);
        map.put("name",node.getAttributes().getNamedItem("name").getNodeValue());
        TextView txtbasicname = new TextView(this);
        txtbasicname.setLayoutParams(new LayoutParams(LayoutParams.WRAP_CONTENT, LayoutParams.FILL_PARENT, 1f));        
        //txtbasicname.setBackgroundColor(Color.WHITE);
        txtbasicname.setTextColor(Color.WHITE);
        String strbasicname =map.put("name",node.getAttributes().getNamedItem("name").getNodeValue());
        txtbasicname.setText(strbasicname);
        linbsc.addView(txtbasicname);

        lin.addView(linbsc);
        LinearLayout linthrd = new LinearLayout(this);
        linthrd.setOrientation(LinearLayout.HORIZONTAL);
        map.put("venuetype",node.getAttributes().getNamedItem("venuetype").getNodeValue());
        TextView txtbasicvenuetype = new TextView(this);
        txtbasicvenuetype.setTextColor(Color.WHITE);
        txtbasicvenuetype.setPadding(5, 0, 0, 0);
        String strbasicvenuetype =map.put("venuetype",node.getAttributes().getNamedItem("venuetype").getNodeValue());
        txtbasicvenuetype.setText(strbasicvenuetype+"-");
        linthrd.addView(txtbasicvenuetype);

        lin.addView(linthrd);
        LinearLayout linforth = new LinearLayout(this);
        linforth.setOrientation(LinearLayout.HORIZONTAL);
        map.put("address",node.getAttributes().getNamedItem("address").getNodeValue());
        TextView txtbasicaddress = new TextView(this);
        txtbasicaddress.setPadding(5, 0, 0, 0);
        txtbasicaddress.setTextColor(Color.WHITE);
        String strbasicaddress =map.put("address",node.getAttributes().getNamedItem("address").getNodeValue());
        txtbasicaddress.setText(strbasicaddress+",");
        linforth.addView(txtbasicaddress);
        map.put("city",node.getAttributes().getNamedItem("city").getNodeValue());
        TextView txtbasiccity = new TextView(this);
        txtbasiccity.setTextColor(Color.WHITE);
        String strbasiccity =map.put("city",node.getAttributes().getNamedItem("city").getNodeValue());
        txtbasiccity.setText(strbasiccity+",");
        linforth.addView(txtbasiccity);

        LinearLayout linfifth = new LinearLayout(this);
        linfifth.setOrientation(LinearLayout.HORIZONTAL);
        map.put("zip",node.getAttributes().getNamedItem("zip").getNodeValue());
        TextView txtbasiczip = new TextView(this);
        txtbasiczip.setTextColor(Color.WHITE);
        txtbasiczip.setLayoutParams(new LayoutParams(LayoutParams.WRAP_CONTENT, LayoutParams.FILL_PARENT, 1f));         
        String strbasiczip =map.put("zip",node.getAttributes().getNamedItem("zip").getNodeValue());
        txtbasiczip.setText(strbasiczip+".");
        linfifth.addView(txtbasiczip);  
        lin.addView(linfifth);
        linm.addView(lin);
        dataList.add(map); 
        mylist.add(map);


    }

    System.out.println("data list = "+dataList);
    System.out.println("data list = "+dataListfeture);

Answer 1

您可以使用TreeMap轻松排序HashMap

TreeMap sortedMap1=new TreeMap<String, String>(HashMap Object);

TreeMap自动对键进行排序，因此，我们可以得到排序后的keySet()，如下所示

sortedMap1.keySet();

Answer 2

您可以使用TreeMap是一个SortedMap，它将根据其键对数据进行排序。

Answer 3

按如下方式声明HashMap，添加到map中的任何项将自动排序:

// This will create a map that will order the keys, ignoring casing of the strings
// (The 'String.CASE_INSENSITIVE_ORDER' can be removed if not wanted)
TreeMap<String, String> map = new TreeMap<String, String>(String.CASE_INSENSITIVE_ORDER);

这意味着如果你这样做:

map.put("Hij", "145");
map.put("Abc", "321");
map.put("def", "123");

那么输出将是:

("Abc","321")("def"、"123")("Hij"、"145")