PHP jQuery代码混合

如果有人能花时间阅读我的代码，并告诉我在下面的脚本中放入变量$kakka的方法，我将不胜感激。到目前为止，变量$kakka没有任何值，因为php代码就在下面。对不起，我对jQuery一无所知，但我需要这个功能才能工作。

Markup和jQuery

<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8">
<script src="http://code.jquery.com/jquery-latest.js"></script>
<script>
var refreshId = setInterval(function()
{
  $('#puu').fadeOut("slow").text($kakka).fadeIn("slow");
}, 5000);
</script>
</head>
<body>

PHP

<?php
$rs = mysql_query("SELECT * FROM users WHERE id='$_SESSION[user_id]'");
  while 
    ($row= mysql_fetch_array($rs))
    {$starter= $row['id'];
     $user_name= $row['user_name'];}

$starterID=$starter;
$companyID=$_GET['id'];

$input = $_POST['viesti'];

date_default_timezone_set('Europe/Helsinki');
$timestamp = date('h:i', time());

$file = $companyID." and ".$starterID.".txt";

if (file_exists($file)) {
$kakka = $companyID." and ".$starterID.".txt";
} else {
$kakka = $starterID." and ".$companyID.".txt";
}

$current = file_get_contents($kakka);
if(isset($_POST['viesti']) && $_POST['viesti'] != null){
$currents= $current. "<b>$user_name</b> <br> $input $timestampn<br>";
$shipuli= "<b>$user_name</b> <br> $input $timestampn<br>";
file_put_contents($kakka, $currents);
}
echo '<div id="puu">'.$current.$shipuli.'</div>';
?>

<?php
$rs = mysql_query("SELECT * FROM users WHERE id='$_SESSION[user_id]'");
  while 
    ($row= mysql_fetch_array($rs))
    {$starter= $row['id'];
     $user_name= $row['user_name'];}

$starterID=$starter;
$companyID=$_GET['id'];

$input = $_POST['viesti'];

date_default_timezone_set('Europe/Helsinki');
$timestamp = date('h:i', time());

$file = $companyID." and ".$starterID.".txt";

if (file_exists($file)) {
$kakka = $companyID." and ".$starterID.".txt";
} else {
$kakka = $starterID." and ".$companyID.".txt";
}

$current = file_get_contents($kakka);
if(isset($_POST['viesti']) && $_POST['viesti'] != null){
$currents= $current. "<b>$user_name</b> <br> $input $timestampn<br>";
$shipuli= "<b>$user_name</b> <br> $input $timestampn<br>";
file_put_contents($kakka, $currents);
}
echo '<div id="puu">'.$current.$shipuli.'</div>';
?>
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8">
<script src="http://code.jquery.com/jquery-latest.js"></script>
<script>
var refreshId = setInterval(function()
{
  $('#puu').fadeOut("slow").text('<?php echo $kakka;?>').fadeIn("slow");
}, 5000);
</script>
</head>
<body>

需要考虑的一些事项

mysql_query已弃用
不建议在生产中使用jquery最新版本

只需将其回声到一个变量-中

var refreshId = setInterval(function()
{ 
  var kakka = '<?php echo $kakka; ?>';
  $('#puu').fadeOut("slow").text(kakka).fadeIn("slow");
}, 5000);

相关内容

最新更新

热门标签：