我是jQuery的新手,我正在练习淡入淡入,从一个图像开始,然后继续到下一个图像,依此类推。我已经写了一段代码(如下),但想知道是否有更简单或更优雅的编写方法?我尝试了 each() 函数,但似乎不起作用:
<script type="text/javascript" src="jquery/jquery-1.8.2 .min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
//alert($("div img").length);
$("div img").css("display","none");
var delayAmt=0;
for(var x=0;x<$("div img").length;x++){
$("div img:eq("+x+")").delay(delayAmt).fadeIn(1000);
delayAmt+=250;
}
});
</script>
</head>
<body>
<h1>Ripple fade in.</h1>
<div>
<img src="images/hot.jpg" id="target0">
<img src="images/hot.jpg" id="target1">
</div>
</body>
</html>
HTML:
<body>
<h1>Ripple fade in.</h1>
<div id="images">
<img src="images/hot.jpg" id="target0">
<img src="images/hot.jpg" id="target1">
</div>
</body>
</html>
j查询:
$(document).ready(function(){
var delay=0;
$('#images').children('img').each(function () {
$(this).css("display","none");
$(this).delay(delay).fadeIn(1800);
delay += 1000;
});
});
jsFiddle链接在这里: http://jsfiddle.net/salih0vicX/6GZt6/