访问返回参数的组件时出现nottaobjectreference错误

Question

我得到ThisIsNotAObjectReference语法消息时，试图处理一个完全类型的数据引用表达式，像这样:

method getDataReference.
 rr_value = ref #( varStructure ).
endmethod.
data(lr_value) = object->getDataReference( )->structureComponent.

我理解的语法是相同的检索对象引用，但如何处理表达式中的完全类型的数据引用?

Answer 1

不能将方法调用与引用组件访问链接起来。你应该像这样使用辅助变量:

CLASS lcl_class DEFINITION.
PUBLIC SECTION.
 METHODS: getdatareference RETURNING VALUE(rr_value) TYPE REF TO mara.
ENDCLASS.
CLASS lcl_class IMPLEMENTATION.
  METHOD getdatareference.
    DATA: ls_mara TYPE mara.
    rr_value = REF #( ls_mara ).
    SELECT SINGLE * FROM mara INTO rr_value->*.
  ENDMETHOD.
ENDCLASS.
START-OF-SELECTION.
  DATA(lcl)     = NEW lcl_class( ).
  DATA(lv_mara) = lcl->getdatareference( ).
  DATA(l_matnr) = lv_mara->matnr.

Answer 2

我有点猜测你在这里想要实现什么，但据我所知，在你可以访问它们的内容之前，你需要取消引用数据引用。下面的代码扩展了上面发布的代码。

report ztest.
class lcl_test definition.
  public section.
    methods getDataReference
      returning value(rr_value) type ref to tadir.
  private section.
    data varStructure type tadir.
endclass.
class lcl_test implementation.
  method getDataReference.
    varstructure-author = sy-uname.
    rr_value = ref #( varStructure ).
  endmethod.
endclass.
start-of-selection.
  data(object) = new lcl_test( ).
  data(lr_value) = object->getDataReference( ).
  field-symbols <structure> type tadir.
  assign lr_value->* to <structure>. " This is the dereferencing step
  write / <structure>-author.