我试图从这样的函数返回一个ID:
CREATE OR REPLACE FUNCTION fx (myTable text, myValue text) returns int
as $$
DECLARE
sqlQuery TEXT;
resultId INT;
BEGIN
sqlQuery :=
'INSERT INTO '
|| myTable || ' (id, some_column) values'
|| ' ('
|| 'nextval(' || quote_literal('seq_' || myTable) || ')'
|| ',' || myValue
|| ') RETURNING id INTO ' || resultId;
EXECUTE sqlQuery;
RETURN resultId;
END;
$$
LANGUAGE plpgsql;
select fx('some_table', 'some_value');
但是不工作。
我如何从sql查询字符串执行这个ID ?
create or replace function fx (mytable text, myvalue text)
returns int as $body$
declare
sqlquery text;
resultId int;
begin
sqlquery := format ($$
insert into %I (id, some_column) values ($1, $2)
returning id
$$, mytable
);
execute sqlquery
into resultId
using nextval('seq_' || mytable), myvalue;
return resultId;
end;
$body$ language plpgsql;
使用%I
format
标识符传递标识符,使用execute using
标识符传递数据参数